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New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

mg In equilibrium, Fe=T sin θ

mg=T cos θ

 tan θ=Femg=q24π0x2*mg

also  tan θs?=x/2l

Hence, x 2 l = q 2 4π0x2*mg

x 3 = 2 q 2 p 4πε0mg

x=(q2l2π0mg)1/3

Therefore xl1/3

New question posted

2 months ago

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New answer posted

2 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

N = qvB

μ q v B = m d v d t = m v d v d S

μ q B S = m v

S = 3 * 1 0 6 * 4 0 . 3 * 1 0 6 * 0 . 2 = 2 0 0 m

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

0 2 = v 2 2 μ k g S r e l

9 2 * 2 = S r e l = 2 . 2 5 m

New answer posted

2 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

400 * 1 * 12.5 = 500 * 5 * (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

1 u + 1 1 0 = 1 3 5

1 u = 1 3 5 1 1 0 = 2 7 7 0 = 1 1 4 1 u = 1 3 5 1 2 9 = 6 4 3 5 * 2 9 u = 3 5 * 2 9 6 4 = 1 5 . 8 5 t o 1 5 . 8 6

New question posted

2 months ago

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New answer posted

2 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

k Q e 0 . 1 2 + 1 2 m u 2 = k Q e 0 . 1 5 + 1 2 m u 2

k Q e * 0 . 0 3 0 . 1 2 * 0 . 1 5 = 1 2 m * ( v 2 u 2 )

Q = 9 . 1 * 9 9 * 1 0 1 1 1 2

= 7 5 . 0 7 5 * 1 0 1 2 4 π * ( 0 . 1 ) 2 = 5 . 9 7 n C / m 2

New answer posted

2 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

R = u x * T

= g h * 0 . 5 g h * 2 g = h

A B = h + h = 2 h

New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

For better resolution, smaller focal length should be objective.

h0 = 1 cm fe = 4cm.

Q 0 = h 0 2 5 Q = 6 0 h 0 2 5 = h I 4

L 5 1 = h I h 0 = 2 4 0 2 5

L = 14.6 cm

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