Physics Thermodynamics

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New answer posted•a year ago
S
a year ago

  γ mixture   = n 1 C P 1 + n 2 C P 2 n 1 C V 1 + n 2 C V 2 = n 1 γ 1 R γ 1 - 1 + n 2 γ 2 R γ 2 - 1 n 1 R γ 1 - 1 + n 2 R γ 2 - 1

on rearranging we get

n 1 + n 2 γ mix   - 1 = n 1 γ 1 - 1 + n 2 γ 2 - 1 ; 5 γ mix   - 1 = 3 1 / 3 + 2 2 / 3

5 γ mix   - 1 = 9 + 3 = 12 ⇒ γ mixture   = 17 12 + 1 + 5 12 ; γ mix   = 1.42

 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Kindly consider the following Image

 

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

η_A = W_A/Q? = 1 - T/T?
η_B = W_B/Q? ' = 1 - T? /T
W_A = Q? (1 - T/T? ) = Q? - Q?
W_B = Q? ' (1 - T? /T) = Q? /2 (1 - T? /T)
Given W_A = W_B
Q? (1 - T/T? ) = (Q? /2) (1 - T? /T)
Q? (T? /T) (1-T/T? ) = (Q? /2) (1-T? /T)
(T? /T - 1) = (1/2) (1-T? /T)
2T? /T - 2 = 1 - T? /T
2T? /T + T? /T = 3
T = (2T? +T? )/3

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New answer posted•a year ago
S
a year ago

Degrees of freedom (f) = 3 translational + 3 rotational + (2 × 4) vibrational = 14
γ = 1 + 2/f = 1 + 2/14 = 8/7
W = nR? T/ (γ-1) = (1 × 8.3 × (310-300)/ (8/7 - 1) = (83)/ (1/7) = 581 J
As W is positive, work is done by the gas. The solution says W<0, work done on the gas. This implies? T is negative. The question states temperature rises, so work is done on the gas. W = -582J.

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New answer posted•a year ago
S
a year ago

-dT/dt = K [T - Ts]

  • (61-59)/4 = K [ (61+59)/2 - 30]
    -0.5 = K [60 - 30] = 30K
    So, K = -1/60 min? ¹
    Again
  • (51-49)/t = K [ (51+49)/2 - 30]
    -2/t = (-1/60) [50-30] = -20/60 = -1/3
    t = 6 min

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