Physics Thermodynamics

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A
alok kumar singh

Contributor-Level 10

Δ Q = n C p Δ T 160 = n C p 50

Δ Q = n C v Δ T 240 = n C v 100

C p C v = 16 5 * 10 24 = 4 3 1 + 2 f = 4 3 f = 6

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Vishal Baghel

Contributor-Level 10

m ( L ) = m 1 S 1 ( Δ T )

m 3.4 * 10 5 = ( 200 ) ( 4200 ) ( 25 )

m = 61.7

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alok kumar singh

Contributor-Level 10

50 - 40 300 = - k 50 + 40 2 - 20

40 - T 300 - k T + 40 2 - 20 10 40 - T = 25 T * 2 T = 200 - 5 T T = 100 3 33 ? C

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alok kumar singh

Contributor-Level 10

Heat lost by steam =  Heat gained by water and calorimeter.

m * 540 + m * 1 * ( 100 - 31 ) = 200 540 m + 69 m = 1200 m = 1200 609 2

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New answer posted

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alok kumar singh

Contributor-Level 10

After burning, heat exchange occurs between helium and atmospheric. Hence, irreversible, isothermal process.

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alok kumar singh

Contributor-Level 10

The internal energy of one mole of an ideal gas is given by U = (f/2)RT, where f is the number of degrees of freedom.
For a non-linear triatomic molecule (assumed to be a rigid rotator), there are:

3 translational degrees of freedom.

3 rotational degrees of freedom.
Vibrational modes are generally not considered at temperature T unless specified.
Total degrees of freedom f = 3 + 3 = 6.
U = (6/2)RT = 3RT.

 

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