Physics Thermodynamics

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New answer posted

4 weeks ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

x = 8R/2 ; y = 5R/2 ; x/y = 8/5 = 1.6

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Workdone by gas = area enclosed in P-V diagram
= π (2)² lt-atm

New answer posted

4 weeks ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

v = √ (γRT/M) ; V? /V? = √ (T? /T? ) ; V? ' = V√ (363/300)

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

W A B = n R T l n 2 V 1 V 1 = n R T l n 2 .

W B C = P 2 ( V 1 2 V 1 ) = P 2 V 1 = 1 2 n R T                         

[At B, 2P2 V1 = nRT]

W C A = 0   [CA is isochoric process].

W A B C A = W A B + W B C + W C A = n R T ( l n ( 2 ) 1 2 )            

New answer posted

4 weeks ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Q 1 = 2 0 ° C w a t e r 1 0 0 ° s t e a m

Q 1 = m c Δ T + m L

= m [ c Δ T + L ]

= 3 1 0 0 0 = 3 1 * 1 0 3 c a l

Q 2 = 2 9 3 3 7 3 * 3 1 * 1 0 3

 

 

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

x = 8R/2, y = 5R/2
x/y = 1.60

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

U = aP?
PV/ (γ-1) = aP?
P? ³V = a (γ - 1)
PV? ¹? ³ = constant
Comparing with PV? = constant
x = -?
C = R/ (γ-1) + R/ (1-x) = R/ (5/3 - 1) + R/ (1 +? ) = 3R/2 + 3R/4
C = 9R/4

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

According to Newton's law of cooling
(T? -T? )/t = K [ (T? +T? )/2 - T? ]
For 1? cup of coffee,
(90-80)/t = K [ (90+80)/2 - 20]
For 2? cup of coffee,
(80-60)/t' = K [ (80+60)/2 - 20]
Divide (1) by (2)
t'/t = 65/50 ⇒ t' = (13/5)t

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

η = 1 - T sin   k T source   = 0.5

T sin   T source   = 0.5 T sin   = 1 2 * ( 273 + 327 ) = 1 2 * 600 = 300 K = 27 ? C

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Adiabatic curve is more steeper than isothermal.

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