Physics Wave Optics

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

While approaching: v = v? (c / (c - vcosθ)
While receding: v = v? (c / (c + vcosθ)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Initially S? L = 2m


S? L = √2² + (3/2)²
S? L = 5/2 = 2.5 m
? x = S? L - S? L = 0.5 m
So since λ = 1 m. ∴? x = λ/2
So white listener moves away from S? Then? x (= S? L − S? L) increases and hence, at? x = λ first maxima will appear.? x = λ = S? L − S? L.
1 = d - 2 ⇒ d = 3 m.

New answer posted

2 months ago

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Vishal Baghel

Contributor-Level 10

For 2 nd    minima

d s i n ? θ = 2 λ

s i n ? θ = 3 2   (given)

λ d = 3 4

So for 1 st    minima is

d s i n ? θ = λ

s i n ? θ = λ d = 3 4   (from equation (i)

θ = 25.65 ?   (from sin table)

  θ 25 ? .

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2 months ago

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A
alok kumar singh

Contributor-Level 10

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

The distance between two successive bright fringes is fringe width  ( β ) .

β = λ D d = 589 * 10 - 9 * 1.5 0.15 * 10 - 3 = 5.9 m m

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

I = I 0 c o s 2 ? θ

I 0 10 = I 0 c o s 2 ? θ

c o s ? θ = 1 10 = 0.31 < 1 2 which is 0.707

So, θ > 45 ?  and 90 - θ < 45 ?  so only one option is correct i.e. 18.4 ?

Angle rotated should be = 90 ? - 71.6 ? = 18.4 ?  .

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Since speed of light is constant for all colour so red colour and blue colour have different frequencies and different wavelengths.

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2 months ago

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

β = λD/d or β ∝ λ
Also, we know that λ_blue < _orange
So, β_orange > β_blue
So, dist b/w consecutive fringes will decrease.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

v = 1/√με = 1/√ (µ? µ? ε? ε? ) = c/√ (µ? ε? )
v = 3*10? / √ (1*81)
v = 3*10? / 9 m/s
= 0.33 * 10? m/s
= 3.33 * 10? m/s

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