The d and f Block Elements
Get insights from 101 questions on The d and f Block Elements, answered by students, alumni, and experts. You may also ask and answer any question you like about The d and f Block Elements
- 101
Questions
- 0
Discussions
- 0
Active Users
- 0
Followers
Have a question about The d and f Block Elements? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
57. Transition elements form binary compounds with halogens. Which of the following elements will form MF3 type compounds?
(A) Cr
(B) Co
(C) Cu
(D) Ni
57. Transition elements form binary compounds with halogens. Which of the following elements will form MF3 type compounds?
(A) Cr
(B) Co
(C) Cu
(D) Ni
57. (A) and (B)
Cr and Co form tri halide compounds.
56. Which of the following ions show higher spin only magnetic moment value?
(A) Ti3+
(B) Mn2+
(C) Fe2+
(D) Co3+
56. Which of the following ions show higher spin only magnetic moment value?
(A) Ti3+
(B) Mn2+
(C) Fe2+
(D) Co3+
56. (B) and (C)
Magnetic moment of an electron/dipole moment is caused by its intrinsic properties of spin and electric charge. It depends upon the number of unpaired electrons in its valence shell. The more the number of unpaired electrons, the greater will be the value of magnetic momen
55. Which of the following lanthanoids show +2 oxidation state besides the characteristic oxidation state +3 of lanthanides?
(A) Ce
(B) Eu
(C) Yb
(D) Ho
55. Which of the following lanthanoids show +2 oxidation state besides the characteristic oxidation state +3 of lanthanides?
(A) Ce
(B) Eu
(C) Yb
(D) Ho
55. (B) and (C)
Ce (Z = 57) = [Xe] 4f5 5d0 6s2 , O.S. = + 3, + 4
Eu (Z = 63) = [Xe] 4f7 5d0 6s2, O.S. = + 2, + 3
Yb (Z = 70) = [Xe] 4f14 5d0 6s2, O.S. = + 2, + 3
Ho (Z
54. General electronic configuration of actinides is (n−−2)f1−14(n−−1)d0−2ns2. Which of the following actinoids have one electron in 6d orbital?
(A) U (Atomic no. 92)
(B) Np (Atomic no. 93)
(C) Pu (Atomic no. 94)
(D) Am (Atomic no. 95)
54. General electronic configuration of actinides is (n−−2)f1−14(n−−1)d0−2ns2. Which of the following actinoids have one electron in 6d orbital?
(A) U (Atomic no. 92)
(B) Np (Atomic no. 93)
(C) Pu (Atomic no. 94)
(D) Am (Atomic no. 95)
54. (A) and (B)
Electronic configuration:
92U - 5f3 6d1 7s2
93Np - 5f4 6d1 7s2
53. Which of the following actinoids show oxidation states up to +7?
(A) Am
(B) Pu
(C) U
(D) Np
53. Which of the following actinoids show oxidation states up to +7?
(A) Am
(B) Pu
(C) U
(D) Np
53. (B) & (D)
Actinides show a variety of oxidation states like +3, +5, +6 and +7.
From the given option, plutonium and neptunium show all oxidation states up to +7
52. In the form of dichromate, Cr(VI) is a strong oxidizing agent in acidic medium but Mo (VI) in MoO3 and W (VI) in WO3 are not because
(A) Cr(VI) is more stable than Mo (VI) and W (VI)
(B) Mo (VI) and W (VI) are more stable than Cr (VI)
(C) Higher oxidation states of heavier members of group-6 of transition series are more stable
(D) Lower oxidation states of heavier members of group-6 of transition series are more stable.
52. In the form of dichromate, Cr(VI) is a strong oxidizing agent in acidic medium but Mo (VI) in MoO3 and W (VI) in WO3 are not because
(A) Cr(VI) is more stable than Mo (VI) and W (VI)
(B) Mo (VI) and W (VI) are more stable than Cr (VI)
(C) Higher oxidation states of heavier members of group-6 of transition series are more stable
(D) Lower oxidation states of heavier members of group-6 of transition series are more stable.
52. (B) and (C)
For the heavier metals of d-block, higher oxidation state is more favourably stable than the lower oxidation state. For example: Mo (VI) and W (VI) are more stable than Cr (VI). For lighter d-block elements like chromium, +3 oxidation state is more stable. So, Cr (VI) in d
51. Transition elements show magnetic moments due to spin and orbital motion of electrons. Which of the following metallic ions have almost the same spin only magnetic moment?
(A) CO2+
(B) Cr2+
(C) Mn2+
(D) Cr3+
51. Transition elements show magnetic moments due to spin and orbital motion of electrons. Which of the following metallic ions have almost the same spin only magnetic moment?
(A) CO2+
(B) Cr2+
(C) Mn2+
(D) Cr3+
51. (A) & (D)
The magnetic moment of an electron/dipole moment is caused by its intrinsic properties of spin and electric charge. It depends upon the number of unpaired electrons in its valence shell. The more the number of unpaired electrons, the greater will be the value of the magnetic
50. Generally, transition elements and their salts are coloured due to the presence of unpaired electrons in metal ions. Which of the following compounds are coloured?
(A) KMnO4
(B) Ce(SO4)2
(C) TiCl4
(D) Cu2Cl2
50. Generally, transition elements and their salts are coloured due to the presence of unpaired electrons in metal ions. Which of the following compounds are coloured?
(A) KMnO4
(B) Ce(SO4)2
(C) TiCl4
(D) Cu2Cl2
50. (A) & (B)
Due to charge transfer phenomenon, which can be understood, for an instant, an electron is transferred from oxygen to the central metal atom, where oxidation state of metal is reduced by one and oxygen gets converted from O- to O2- .
This transfer imparts Colour to
49. Why is HCl not used to make the medium acidic in oxidation reactions of KMnO4 in acidic medium?
(A) Both HCl and KMnO4 act as oxidizing agents.
(B) KMnO4 oxidises HCl into Cl2 which is also an oxidizing agent.
(C) KMnO4 is a weaker oxidizing agent than HCl.
(D) KMnO4acts as a reducing agent in the presence of HCl.
49. Why is HCl not used to make the medium acidic in oxidation reactions of KMnO4 in acidic medium?
(A) Both HCl and KMnO4 act as oxidizing agents.
(B) KMnO4 oxidises HCl into Cl2 which is also an oxidizing agent.
(C) KMnO4 is a weaker oxidizing agent than HCl.
(D) KMnO4acts as a reducing agent in the presence of HCl.
49. (B) KMnO4 oxidises HCl into Cl2 which is also an oxidizing agent.
HCl is not used in titrations involving KMnO4 as it produces unsatisfactory results. When HCl is added to KMnO4, it itself acts as reducing agent and coverts HCl to Cl2.
48. Although zirconium belongs to 4d transition series and hafnium to 5d transition series even then they show similar physical and chemical properties because
(A) Both belong to d-block
(B) Both have same number of electrons
(C) Both have similar atomic radius
(D) Both belong to the same group of the periodic table
48. Although zirconium belongs to 4d transition series and hafnium to 5d transition series even then they show similar physical and chemical properties because
(A) Both belong to d-block
(B) Both have same number of electrons
(C) Both have similar atomic radius
(D) Both belong to the same group of the periodic table
48. (C) both have similar atomic radius
As an effect of lanthanide contraction, zirconium and hafnium have similar radii of 160 pm and 159 pm respectively. Due to this similarity in their size, they show similar physical and chemical properties.
Lanthanide contraction: Because the el