Units and Measurement

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New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

[ F ] = M L T 2 M = F L 1 T 2

[ ρ ] = M L 3 = F L 1 T 2 L 3 = F L 4 T 2

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

μ 0 = B 0 H = N A 2

[ μ 0 ] = [ M 1 L 1 T 2 A 2 ]

It is not dimensionless

New answer posted

8 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

RH : m-1

h : kgm2 s-1

μ B : k g m 1 s 2          

η : k g m 1 s 1              

New answer posted

8 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Δ z z * 1 0 0 = 3 Δ x x * 1 0 0 + 1 2 Δ y y * 1 0 0

= 3 * 4 + 1 2 * 1 2

= ( 1 2 + 6 ) %

= 1 8 %

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

P = E L 2 M 5 G 2

= [ M L 2 T 2 ] [ M L 2 T 1 ] 2 [ M 5 ] [ M 1 L 3 T 2 ] 2

= M 0 L 0 T 0

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Pitch = 0.5 mm

Least count = p i t c h d i v i s i o n = 0 . 5 m m 5 0 = 0 . 0 1 m m

True Reading = 5mm + 20 * 0.01 – 5 * 0.01 = 5.15 mm

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

z = A 2 B 3 C 4

The relative error in z is given by

Δ z z = 2 Δ A A + 3 Δ B B + 4 Δ C C

New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Δ z z * 1 0 0 = 3 Δ x x * 1 0 0 + 1 2 Δ y y * 1 0 0

= 3 * 4 + 1 2 * 1 2

= ( 1 2 + 6 ) %

= 1 8 %

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

A. Torque   (iii) Nm

B. Stress  (iv) Nm-2

C. Latent Heat  (ii) J kg-1

D. Power  (i) Nm S-1

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given, m = 0.6 ±  0.006

p = m v = m π r 2 l

Δ ρ ρ * 1 0 0 = Δ m m * 1 0 0 + 2 Δ r r * 1 0 0 + Δ l l * 1 0 0

= 1 + 2 * 1 + 1

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