Units and Measurement

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New answer posted•a year ago

Units and Measurement Class 11th

If energy E, volume V and time T are taken as fundamental units, the dimensional formula of the force will be

8 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

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New answer posted•a year ago

Units and Measurement Class 11th

Assertion (A) Two similarly charged bodies may attract each other.

Reason (R) When charge on one body (Q) is much greater than that on another (q) and they are close enough to each other, then force of attraction between Q and induced charges exceeds the force of repulsion between Q and q.

4 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Kindly go through the solution

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New answer posted•a year ago

Units and Measurement Class 11th

Identify the vector quantity among the following

3 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Angular momentum is an axial vector along axis of rotation.

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New answer posted•a year ago

Units and Measurement Class 11th

Identify the vector quantity among the following

3 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Angular momentum is an axial vector along axis of rotation.

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New answer posted•a year ago

Units and Measurement Class 11th

Identify the vector quantity among the following

3 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Angular momentum is an axial vector along axis of rotation.

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New answer posted•a year ago

Units and Measurement Class 11th

Can we call the trailing zeroes in numbers as significant numbers?

3 Views|Posted a year ago

Asked by Syed Aquib Ur Rahman

Answered by

Syed Aquib Ur Rahman | Contributor-Level 10

a year ago

We cannot call the trailing zeroes as significant numbers. If you remember from the rules, it needs to have a decimal point somewhere to be considered as one. What is recommended is that one can use the measure as to the power of 10.

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New answer posted•a year ago

Units and Measurement Class 11th

Voltage and resistance for a resistor are measured as V = 200 ± 5 volts and R = 20 ± 0.2 2. The percentage error in current  isx. Find the value of 10x

4 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

%error= $(\frac{d V}{V} + \frac{d R}{R}) * 100$

$= (\frac{5}{200} + \frac{0.2}{20}) * 100$

= 3.5

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New answer posted•a year ago

Units and Measurement Class 11th

Match the two columns.

Column 1

Column 2

P.

Surface tension

1.

[ML²T^–2]

Q.

Viscosity

2.

[ML²T^–1]

R.

Angular momentum

3.

[ML^–1T^–1]

S.

Rotational kinetic energy

4.

[ML⁰T^–2]

6 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

$S = \frac{F}{L}$

[S] = [MT^–2]

$F = n A \frac{d v}{d x}$

$η = \frac{M L T^{- 2} \cdot T}{L^{2}} = M L^{- 1} T^{- 1}$

$\vec{L} = \vec{r} \times \vec{p}$

L º [ML²T^–1]

$K E = \frac{1}{2} l ω^{2}$

KE º ML²T⁻²

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New answer posted•a year ago

Units and Measurement Class 11th

A pendulum completes 50 oscillations in 40 seconds. If the length of pendulum is (20 ± 0.2) cm and resolution of watch is 1 second, find the percentage error in calculation of g.

4 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

$T = 2 π \sqrt[]{\frac{I}{g}}$

$g = \frac{4 π^{2} I}{T^{2}}$

$\frac{Δ g}{g} = \frac{Δ I}{I} + \frac{2 Δ T}{T}$

$= \frac{0.2}{20} + 2 (\frac{1}{40})$

= 6%

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New answer posted•a year ago

Units and Measurement Class 11th

If $E = \frac{A - x^{2}}{B t}$  where E is energy, x is displacement and t is time. Find dimensions of AB

5 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

[A] = L²

$B = \frac{x^{2}}{t E} \equiv \frac{L^{2}}{T M L^{2} T^{- 2}} = \frac{1}{M T^{- 1}}$

[B] = M^–1T

[AB] = [M^–1L²T]

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	Column 1		Column 2
P.	Surface tension	1.	[ML²T^–2]
Q.	Viscosity	2.	[ML²T^–1]
R.	Angular momentum	3.	[ML^–1T^–1]
S.	Rotational kinetic energy	4.	[ML⁰T^–2]

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