Units and Measurement

Angular momentum is an axial vector along axis of rotation.

Angular momentum is an axial vector along axis of rotation.

We cannot call the trailing zeroes as significant numbers. If you remember from the rules, it needs to have a decimal point somewhere to be considered as one. What is recommended is that one can use the measure as to the power of 10.  

%error= $\left(\frac{dV}{V}+\frac{dR}{R}\right)*100$  

$=\left(\frac{5}{200}+\frac{0.2}{20}\right)*100$                          

= 3.5

$S=\frac{F}{L}$  

[S] = [MT^–2]

$F=nA\frac{dv}{dx}$  

$\eta =\frac{ML{T}^{-2}\cdot T}{L^2}=M{L}^{-1}{T}^{-1}$

$\overrightarrow{L}=\overrightarrow{r}*\overrightarrow{p}$

L º [ML²T^–1]

$KE=\frac{1}{2}l{\omega }^2$  

KE º ML²T⁻²

$T=2\pi \sqrt[]{\frac{I}{g}}$

$g=\frac{4{\pi }^{2}I}{T^2}$

$\frac{\Delta g}{g}=\frac{\Delta I}{I}+\frac{2\Delta T}{T}$

$=\frac{0.2}{20}+2\left(\frac{1}{40}\right)$

= 6%

[A] = L²

$B=\frac{x^2}{tE}\equiv \frac{L^2}{TM{L}^2{T}^{-2}}=\frac{1}{M{T}^{-1}}$            

[B] = M^–1T

[AB] = [M^–1L²T]

10 M = 11 V

Þ  1V =   $\frac{10}{11}$ * 5 mm

Þ  LC = |M – V|

      =   $\frac{5}{11}$ mm

F = Ma = ML T²

-> T² = ML/F

F

In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.

Hence, in 40.40 all zeros are significant