Units and Measurement

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New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Least count = Pitch / (Total divisions on circular scale)
In 5 revolution, distance travelled = 5mm
? In 1 revolution, distance travelled = 1mm
So least count = 1/50 = 0.02mm = 0.002 cm
So, Assertion is not correct but reason is correct

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Dimension of B = [L? ¹]
Dimension of D = [T? ¹]
Dimension of A = [MLT? ²]
The dimensional formula of AD/B
= [MLT? ²] [T? ¹]/ [L? ¹] = [ML²T? ³]

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Since, x 2 α k T  should be dimensionless.

So, dimension of   α , [ α ] = L 2 M L 2 T 2 = M 1 T 2

Dimension of  α β 2 should be that of W.

So, [ α β 2 ] = M L 2 T 2  

[ β 2 ] = M L 2 T 2 M 1 T 2 = M 2 L 2 T 4 [ β ] = M L T 2            

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

W=α2βeβx2kT

[βx2]= [kT]= [ML2T2]

β=MT2

[W]= [α2β] [ML2T2]= [α2] [MT2] [α2]= [L2] [α]= [L]

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

T = 2 π L g o r T 2 = 4 π 2 ( L g )

g = 4 π 2 ( L T 2 )

Δ g g % = ( Δ L L + 2 Δ T T ) % = [ 1 m m 1 m + 2 * 0 . 0 1 1 . 9 5 ] * 1 0 0 % = ( 0 . 0 0 1 + 0 . 0 1 0 2 ) * 1 0 0 = 1 . 1 3 %

New answer posted

3 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

L C = 1 1 0 0 m m = 0 . 0 1 m m

Zero error = +0.08 mm.

Diameter = 1 + 72 * 0.01 – 0.08 = 1.64 mm

Radius = 0.82 mm

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

14πε0|e|2hc=14πε0|e|2r2*r2hcλ*λ=Fr*rE*λ

Dimension of 'Fr' and 'E' are same dimensionless

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

From principle of homogeneity

[ F ] = [ α t 2 ] = [ β t ]

[α]=[F][t2] and [β]=[F][t]

[ α ] [ t ] = [ β ]

αtβ= dimensionless 

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

V . C = M S D V S D     … (i)

given :  (N+1)VSD=NMSD

VSD= (NN+1)MSD     … (ii)

From (1) and (2)

V . C = ( MSD ) N N + 1 ( MSD )

=MSD (1NN+1)=MSDN+1

= 0 . 0 1 N + 1 = 1 1 0 0 ( N + 1 )

New answer posted

3 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Divided into 10 parts

R = ρ l A

R = ρ l 1 0 A = R 1 0

RS=5*R10 [series] 

R S = 5 0

R P = R 5 0 [  parallel  ]

R eq  = R S + R P

= 5 2 Ω

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