Units and Measurement
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New answer posted
2 months agoContributor-Level 10
Pitch p = 0.5 mm
Device has +ve zero error
R = 6p + 28p/50 - 4p/50 = 6p + 24p/50; 3mm + (24/50) * 0.5 = 3.24 mm
New answer posted
2 months agoContributor-Level 10
F = ηAdv / dx
η = F (dx/dv) (1/A) = m * a * time * (1/area) = MV/A
New answer posted
2 months agoContributor-Level 10
Since, should be dimensionless.
So, dimension of
Dimension of
So,
New answer posted
2 months agoContributor-Level 10
E ∝ F? A? T?
[M¹L²T? ²] ∝ [M¹L¹T? ²]? [LT? ²]? [T]?
a = 1
a + b = 2 ⇒ b = 1
-2a - 2b + c = -2
⇒ c = 2
a = 1 b = 1 c = 2
E ∝ [F] [A] [T²]
New answer posted
2 months agoContributor-Level 10
Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm
New answer posted
2 months agoContributor-Level 9
As the factors controlling temperature and voltage supply are beyond prediction and control so the error occurred due to unpredictable fluctuations of temperature and voltage would be random errors.
New answer posted
2 months agoContributor-Level 10
The dimensional formula for energy E is [ML²T? ²].
The dimensional formula for the gravitational constant G is [M? ¹L³T? ²].
The ratio E/G has dimensions: [ML²T? ²] / [M? ¹L³T? ²] = [M²L? ¹T? ].
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