Units and Measurement
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New answer posted
2 months agoContributor-Level 10
As the factors controlling temperature and voltage supply are beyond prediction and control so the error occurred due to unpredictable fluctuations of temperature and voltage would be random errors.
New answer posted
2 months agoContributor-Level 10
V = (4/3)πr³
⇒ ΔV/V = 3 (Δr/r) ⇒ Relative error
% error in volume = (ΔV/V) * 100 = 3 (Δr/r) * 100 = 3 * (0.85/7.50) * 100 = 33.999 ≈ 34
New answer posted
2 months agoContributor-Level 10
Positive zero error = 0.02 cm
Reading = 8.5 + 6 * 0.01 = 8.56 cm
Actual reading = Reading - Positive zero error
Actual reading = 8.56 - 0.02 = 8.54 cm
New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
Since significant figures show the degree of correctness of any measurement, so in any mathematical calculation we cannot increase the number of significant digits. Because the four reading has 3 significant digits so the answer should also have 3 significant digits only.
New answer posted
2 months agoContributor-Level 10
x = (IFV²)/ (WL? )
I = [ML²]
F = [MLT? ²]
V² = [L² T? ²]
W = [ML² T? ²]
Q? = [L? ]
X = [ML? ¹ T? ²]
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