Aldehydes, Ketones and Carboxylic Acids
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4 months agoContributor-Level 10
1. Di-tertbutyl, ketone 2. +I effect donates e- . Br group will show +I effect along the chain but as I effect is distance dependent effect it will die as the distance increase.+I effect of alkyl group will reduce the acidity of a compound whereas –I effect will increase the acidity, I effects are distance dependent, correct order will be (CH3)2CHCOOH< CH3CH2CH2COOH< CH3CH (Br)CH2COOH < CH3CH2CH (Br)COOH. 3. As we know the electron releasing groups (ERG) reduces the acidic strength of the compound (via inductive effect) whereas the electron withdrawing group (EWG) will increase the acidic strength of compound, and methoxy group is
New answer posted
4 months agoContributor-Level 10
ANSWER: Given compound is having 8 carbons, and on reaction with chromic acid C is converted back into B, as chromic acid reaction couldn't add any carbon hence both alcohol and acid must contain 4 carbons and it is given in the question that on dehydration C will give but-1-ene so alcohol will be butan-1-ol (C) and acid will be butan-1-oic acid (B) and given reaction will be ester hydrolysis,
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4 months agoContributor-Level 10
Since the given compound with molecular formula C9H10O form a 2,4-DNP derivative and reduce Tollen's reagent, it must be an aldehyde. Since it undergoes cannizzaro reaction, therefore CHO group is directly attached to the benzene ring.
Since on vigorous oxidation, it gives 1,2-benzene dicarboxylic acid, therefore it must be ortho-substituted benzaldehyde. The only o-substituted aromatic aldehyde having molecular formula C9H10O is o—ethyl benzyldehyde all the reaction can show now be explained on the basis of this structure-
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4 months agoContributor-Level 10
i) Taking two molecules of propanal, one which acts as a nucleophile and the other as an electrophile.
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4 months agoContributor-Level 10
1. Butane-1,3-diol -
Ethanol react dilute alkali produces 3-hydroxybutanal which on Reduction gives butane-1, 3-diol on reduction.
New answer posted
4 months agoContributor-Level 10
Ans
Aldehydes and ketones having at least one α-hydrogen undergo aldol The compounds
(ii) 2-methylpentanal
(v) cyclohexanone
(vi) 1-phenylpropanone
(vii) phenylacetaldehyde
contain one or more α-hydrogen atoms. Therefore, these undergo aldol condensation.
Aldehydes having no α-hydrogen atoms undergo Cannizzaro The compounds
(i) Methanal
(iii) Benzaldehyde
(ix) 2, 2-dimethylbutanal
do not have any α-hydrogen. Therefore, these undergo cannizzaro reactions.
Compound (iv) Benzophenone is a ketone having no α-hydrogen atom and compound (viii) Butan-1-ol is an alcohol. Hence, these compounds do not undergo either aldol condensation or canni
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