B.Tech Cut-off

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New answer posted

4 months ago

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R
Rashmi Sinha

Contributor-Level 10

Indraprastha Institute of Information Technology, Delhi, accepts the JEE Main entrance exam, followed by JAC Delhi counselling for BTech admission. As per the IIIT Delhi JAC Delhi cutoff 2025, the Round 1 closing ranks varied between 7429 and 31355 for the students belonging to the General AI quota. Of all the courses, the most competitive was Computer Science and Economics. For IIIT Delhi branch-wise cutoff 2025 for Round 1, refer to the table below. The cutoff data provided below is for the general AI quota. 

CourseJAC Delhi Round 1 Cutoff 2025 
B.Tech. in Computer Science and Economics7429
B.Tech. in Computer Science and Design9594
B.Tech. in Computer Science and Social Science13365
B.Tech. in Computer Science and Biosciences16098
B.Tech. in Computer Science and Engineering19158
B.Tech. in Computer Science and Applied Mathematics20194
B.Tech. in Electronics and VLSI Engineering20531
B.Tech. in Computer Science and Artificial Intelligence29567
B.Tech. in Electronics and Communication Engineering31355

New answer posted

4 months ago

0 Follower 15 Views

R
Rashmi Sinha

Contributor-Level 10

The NSUT BTech cutoff 2025 has been released for Round 1 based on JEE Main ranks, followed by JAC Delhi counselling. The cutoff was released as opening and closing ranks for different categories of students belonging to the AI and HS quotas. Among the general AI quota, the closing ranks for B.Tech. admission ranged between 2092 and 12892. A detailed specialization-wise break-up is tabulated below:

CourseJAC Delhi Round 1 Cutoff 2025
B.Tech. in Computer Science and Engineering (Artificial Intelligence)2092
B.Tech. in Computer Engineering2612
B.Tech. in Computer Science and Engineering (Data Science)3161
B.Tech. in Information Technology4013
B.Tech. in Mathematics and Computing Engineering4181
B.Tech. in Computer Science and Engineering (Big Data Analytics) (CSDA)4229
B.Tech. in Information Technology (Network and Information Security)4773
B.Tech. in Computer Science and Engineering (IOT)5145
B.Tech. in Electronics and Communication Engineering5540
B.Tech. in Electronics Engineering (VLSI Design & Technology)6389
B.Tech. in Electronics and Communication Engineering (Artificial Intelligence and Machine Learning) (ECAM)6427
B.Tech. in Electrical Engineering7456
B.Tech. in Instrumentation and Control Engineering8803
B.Tech. in Mechanical Engineering10182
B.Tech. in Mechanical Engineering (Electric Vehicles)10281
B.Tech. in Civil Engineering12457
B.Tech. in Biotechnology12513
B.Tech. in Geoinformatics Engineering12892

New answer posted

4 months ago

0 Follower 168 Views

R
Rashmi Sinha

Contributor-Level 10

If you belong to the OBC category under the HS quotas, you must target to secure up to 101206 or less to be eligible for CSE admission. Just to let you know, NSUT offers CSE with other specialsiation, such as AI & Data Science, IOT, etc. Hence, cutoff ranks vary for different specializations, rounds, categories, and quotas. Netaji Subhas University of Technology JAC Delhi cutoff 2025 for Round 1 is out, wherein the closing ranks ranged between 19550 and 215711 for the OBC category. Candidates can refer to the table below to view the JAC Delhi cutoff 2025 for Round 1 across all the CSE specialisations: 

CourseJAC Delhi Round 1 Cutoff 2025 (OBC-HS)
B.Tech. in Computer Science and Engineering (Artificial Intelligence)19550
B.Tech. in Computer Engineering37497
B.Tech. in Computer Science and Engineering (Data Science)45515
B.Tech. in Computer Science and Engineering (Big Data Analytics) (CSDA)83766
B.Tech. in Computer Science and Engineering (IOT)101206

New answer posted

4 months ago

0 Follower 14 Views

R
Rashmi Sinha

Contributor-Level 10

DTU JAC Delhi cutoff 2025 is out for candidates seeking admission to BTech course. For the General HS quota, the closing ranks varied between 6105 and 48205 and for the OBC HS category, the cutoff ranks were between 42250 and 204614 for BTech admission. More detailed category-wise DTU Cutoff 2025 is given in the table below:

CategoryJAC Delhi Round 1 Cutoff 2025 (HS Quota)
General6105 - 48205
OBC42250 - 204614
SC80206 - 343565
ST304203 - 1353901
EWS21103 - 122877
PWD148004 - 1360126

 

New answer posted

4 months ago

0 Follower 4 Views

R
Rashmi Sinha

Contributor-Level 10

National Institute of Technology Kurukshetra accepts the JEE Main entrance exam for admitting students to its BTech course. The NIT Kurukshetra cutoff 2025 has been released for Round 1, wherein the closing ranks varied between 281 and 46438 for female candidates. For NIT Kurukshetra, the cutoff ranks were released under both AI and HS quotas. For the Home State quota, the closing ranks were between 1201 and 52806 for female category candidates. Detailed branch-wise cutoff ranks are tabulated below:

Course JEE Main Round 1 Closing Ranks 2025 
Architecture (5 Years, Bachelor of Architecture)281
Computer Science and Engineering (4 Years, Bachelor of Technology)11075
Computer Science and Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))13074
Artificial Intelligence and Machine Learning (4 Years, Bachelor of Technology)13117
Artificial Intelligence and Data Science (4 Years, Bachelor of Technology)14422
Information Technology (4 Years, Bachelor of Technology)14711
Mathematics and Computing (4 Years, Bachelor of Technology)15118
ROBOTICS & AUTOMATION (4 Years, Bachelor of Technology)16686
Electronics and Communication Engineering (4 Years, Bachelor of Technology)17473
Electronics and Communication Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))18486
Microelectronics & VLSI Engineering (4 Years, Bachelor of Technology)21653
Electrical Engineering (4 Years, Bachelor of Technology)24455
Industrial Internet of Things (4 Years, Bachelor of Technology)24622
Electrical Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))25783
Mechanical Engineering (4 Years, Bachelor of Technology)33976
Mechanical Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))38789
Civil Engineering (4 Years, Bachelor of Technology)40960
SUSTAINABLE ENERGY TECHNOLOGIES (4 Years, Bachelor of Technology)41864
Production and Industrial Engineering (4 Years, Bachelor of Technology)42545
Civil Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))46438

New answer posted

4 months ago

0 Follower 7 Views

R
Rashmi Sinha

Contributor-Level 10

NIT Bhopal JEE Main cutoff 2025 has been released for Round 1, wherein the closing ranks varied between 8547 and 39322 for the students belonging to the General AI quota. The cutoff ranks vary for different courses, specializations, rounds, categories, and quotas. Tabulated below is Round 1 of the MANIT Bhopal BTech cutoff 2025 for the general AI category candidates:

CourseJEE Main Round 1 Cutoff 2025 
B.Tech. in Electronics and Communication Engineering12706
B.Tech. in Electrical Engineering18379
B.Tech. in Computer Science and Engineering8547
B.Tech. in Mechanical Engineering25728
B.Tech. in Chemical Engineering31982
B.Tech. in Civil Engineering36084
B.Tech. in Materials and Metallurgical Engineering39322
B.Tech. + M.Tech. in Mathematics and Data Science13766
B.Tech. in Energy and Electrical Vehicle Engineering23117
B.Tech. + M.Tech. in Engineering and Computational Mechanics20056

New answer posted

4 months ago

0 Follower 7 Views

R
Rashmi Sinha

Contributor-Level 10

MANIT Bhopal JEE Main cutoff 2025 for the General AI category candidates for Round 1 varied between 8547 and 39322 for admission to the BTech course across multiple specialisations. The one with the lowest cutoff rank of 8547 was Computer Science and Engineering. For the OBC category candidates, the JEE Main cutoff ranks were between 3141 and 13739. Candidates can refer to the table below to view the Round 1 cutoff range for different categories for admission to the BTech course:

CategoryJEE Main Round 1 Cutoff 2025 
General8547 - 39322
OBC3141 - 13739
SC1728 - 6702
ST630 - 2759
EWS1223 - 5645
PWD172 - 2116

New answer posted

4 months ago

0 Follower 62 Views

R
Rashmi Sinha

Contributor-Level 10

NIT Calicut admits students to its BTech courses based on JEE Main ranks, followed by JoSAA counselling. If you belong to the general category under the AI quota, the minimum rank required to be eligible for Round 1 admission was 4678 or less. The maximum cutoff rank went up to 28830. Candidates can refer to the table below to view the JEE Main first round closing ranks for the B.Tech. programme across multiple specialisations for the General AI quota:

CourseJEE Main Round 1 Cutoff 2025 
B.Tech. in Chemical Engineering21138
B.Tech. in Computer Science and Engineering4678
B.Tech. in Civil Engineering28830
B.Tech. in Electrical and Electronics Engineering9624
B.Tech. in Electronics and Communication Engineering7380
B.Tech. in Mechanical Engineering15624
B.Tech. in Production Engineering28078
B.Tech. in Biotechnology26457
B.Tech. in Engineering Physics13924
B.Tech. in Materials Science and Engineering26840
B.Tech. in Energy Engineering18696

 

New answer posted

4 months ago

0 Follower 10 Views

S
Sanjana Singh

Contributor-Level 6

IIIT Manipur JEE Main cutoff 2025 has been released for the round 1. The cutoff was released for different categories belonging to the All India quota. The cutoff ranks among the General AI category candidates was between the range of 45341 and 56825. Out of all the specialisations, the most competitive one was B.Tech. in Computer Science and Engineering (Quantum Technologies)

Among the OBC AI category candidates, the cutoff ranks varied between 15760 and 18735. Among the OBC AI category candidates also, the toughest specialisation was B.Tech. in Computer Science and Engineering (Quantum Technologies).

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