B.Tech Cut-off
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New answer posted
11 months agoContributor-Level 10
Kumaraguru College of TechnologyTNEA cutoff 2024 ranged between 3524 and 47326 for BE/ BTech admission among the General AI quota. So, students with a cutoff of 16402 are eligible to secure a seat at Kumaraguru College of Technology. Since you have not mentioned in which course you want to take admission, I am considering you don't have any specific course preference. Hence, a list of all the BE specialisations is tabulated below up to a cutoff rank of 16402 for Kumaraguru College of Technology BE/ BTech admission through TNEA counselling:
| Course | TNEA Last Round Cutoff 2024 |
| B.E. in Computer Science and Engineering | 3524 |
| B.E. in Electronics and Communication Engineering | 4671 |
| B.Tech. in Information Technology | 4978 |
| B.Tech. in Artificial Intelligence and Data Science | 5102 |
| B.E. in Electrical and Electronics Engineering | 8684 |
| B.E. in Electronics and Instrumentation Engineering | 11442 |
| B.E. in Aeronautical Engineering | 13779 |
| B.Tech. in Biotechnology | 14451 |
| B.E. in Mechatronics Engineering | 16402 |
New answer posted
11 months agoContributor-Level 10
Course | TNEA Last Round Cutoff 2024 |
B.E. in Electronics and Communication Engineering | 2125 |
B.E. in Electrical and Electronics Engineering | 4902 |
B.E. in Computer Science and Engineering | 1561 |
B.E. in Mechanical Engineering | 11045 |
B.E. in Civil Engineering | 12483 |
New answer posted
a year agoContributor-Level 9
IIT Dhanbad offers a four-year BTech degree course in Computer Science & Engineering. Admission to the four-year course is entrance-based. It is also one of the top BTech branches. As per the IIT ISM Dhanbad's past years records, almost 100% of students from the CSE department get placed.Ranking: IITs have a higher ranking and reputation among the engineering colleges in India and the world. Seven IITs are in the top 10 of the NIRF 2020 ranking, while NIT Trichy is ranked 9th among the engineering colleges and 1st among the NITs.
New answer posted
a year agoContributor-Level 10
IIT Goa JEE Advanced Cutoff 2024 was released for it's final rounds. The cutoff ranks ranged between 2002 and 4696, among the General AI category candidates. The table below provides the branch-wise cutoff for the General AI category during it's last round:
| Course | 2024 |
|---|---|
| B.Tech. in Mechanical Engineering | 4696 |
| B.Tech. in Computer Science and Engineering | 2002 |
| B.Tech. in Electrical Engineering | 3573 |
| B.Tech. in Mathematics and Computing Engineering | 2593 |
New answer posted
a year agoBeginner-Level 5
The minimum ranks required to receive a call from IIT Delhi vary based on the course, category, and quota. For the JEE Advanced 2024 Round 5 Seat Allotment, the closing ranks for the General category ranged approximately between 116 and 4849, depending on the specific program.
Please note that these are estimates from the previous year. For the most accurate and up-to-date cutoff details, it is recommended to check the official IIT Delhi website or other reliable sources regularly.
New answer posted
a year agoContributor-Level 10
IIT Varanasi Cutoff 2024 was concluded for MSc admission. The Institute provides admission to MSc courses on the basis of performance in IIT JAM exam. During the last-round cutoff for MSc admission, the cutoff was released for - MSc in Physics and MSc in Chemistry. Candidates can check the cutoff ranks for the General AI Category in the table below:
| Course | 2024 |
|---|---|
| M.Sc. in Physics | 641 |
| M.Sc. in Chemistry | 673 |
New answer posted
a year agoContributor-Level 10
IIT Varanasi Cutoff 2024 was concluded for admission to various BTech/Integrated BTech/BArch courses. The Cutoff was released for different categories under the AI quota. For the General AI category candidates, the cutoff ranks for different BTech and other courses ranged between 1071 and 22390. Among the OBC AI category candidates, the cutoff ranks across multiple specialisations closed at a range of 524 and 8177.
The table provided below shows the IIT Varanasi 2024 Cutoff for the General AI Category candidates:
New answer posted
a year agoContributor-Level 10
Sir M Visvesvaraya Institute Of Technology accepts COMEDK entrance exam scores for admission to the BE/ BTech courses. For 2024 admission, COMEDK cutoff has been announced, wherein Computer Science & Engineering stands out as the most in-demand course with a the lowest round 3 closing rank of 23135 for the General AI quota. The easiest course to get into Sir M Visvesvaraya Institute Of Technology was B.Tech. in Electronics and Computer Engineering which has a cutoff rank of 98269.
Candidates can refer to the table below to check out the COMEDK cutoff 2024 for Sir M Visvesvaraya Institute Of Technology for the General AI categ
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