Chemical Kinetics
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New answer posted
8 months agoContributor-Level 10
4.2 Given-
Initial concentration (A1) = 0.5M
Final concentration (A2) = 0.4M
Time = 10 mins.
The formula for average rate of the reaction is,
rav = -1/2 X Δ{A} / Δt → Equation 1
? {A} = (A2)-( A1), the equation 1 is written as,
rav = -1/2 X A2 - A1 / Δt
= -1/2 X 0.4-0.5 / 10
= -1/2 X 0.1 / 10
= 0.005 mol L-1 min-1
= 5 * 10-3 mol L-1 min-1
The average rate of the reaction is 5 * 10-3 mol L-1 min-1
New answer posted
8 months agoContributor-Level 10
4.1 Given-
Initial concentration (R1) = 0.03M
Final concentration (R2) = 0.02M
Time = 25 mins.
The formula for average rate of the reaction is,
rav = - Δ{R} / Δt → Equation 1
? {R} = (R2)-( R1), the equation 1 is written as,
rav = - R2 - R1 / Δt
= -0.02-0.03 / 25
= 4 X 10-4 mol L-1 min-1
The average rate of reaction in seconds is given by,
= 4 X 10-4 mol L-1 / 60 S
(dividing by 60 to convert minutes to seconds)
= 6.6 * 10-6 mol L-1 s-1
The average rate of the reaction in minutes is 4 * 10-4 mol L-1 min-1 and in seconds is 6.6 * 10-6 mol L-1 s-1
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