Chemical Kinetics

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(i)- (c) ; (ii)- (a) ; (iii)- (d); (iv)- (f); (v)- (b); (vi)- (b)

A catalyst can influence the rate of a process by lowering the activation energy

When it comes to molecularity, there can't be a fraction or a zero.

The second half life of

This is a Matching Type Question as classified in NCERT Exemplar

(i)- (a) ; (ii)- (b) ; (iii)- (b); (iv)- (a)

 A zero-order reaction is one in which the reactant concentrations do not change over time and the rate of concentration remains constant.

A first-order reaction is one in which the rate

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Correct options: A and D

The pace of a reaction that is directly proportional to the concentration of the reacting substance is known as a first order reaction. 

Y=mn

k = $\frac{2.303}{\mathrm{t}}\mathrm{}$ log  $\frac{\mathbf{ }\mathbf{a}}{\mathbf{a}-\mathbf{x}\mathbf{ }}$

t = $\frac{2.303}{\mathrm{k}}\mathrm{}$ log $\frac{\mathbf{ }\mathbf{a}}{\mathbf{a}-\mathbf{x}\mathbf{ }}$

x= a- $\frac{\mathbf{a}}{2}$

x= $\frac{\mathbf{a}}{2}$

t $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.\mathbf{}$ _{= $\frac{2.303}{\mathrm{k}}\mathrm{}$} log $\frac{\mathbf{ }\mathbf{a}}{\mathbf{a}-\frac{\mathbf{a}}{2}\mathbf{ }}$  &nb

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Correct options: A and D

A Zero order reaction = [R] =  ( - k)t +  [R]₀

y = (m ×  ) + c

x = t (time)

y =  [R]concentration

Slope (m) =  - k

Intercept (c) =  [R]₀

  $\frac{\left. [\mathbf{R}\right]\mathbf{ }-\mathbf{ }{\left. [\mathbf{R}\right]}_0}{\mathbf{t}}$ =  - k

$\frac{\left. [\mathbf{R}\right]\mathbf{ }-\mathbf{ }{\left. [\mathbf{R}\right]}_0}{\mathbf{t}}$ =  -

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct options: B, C and D

Catalysts reduce the activation energy of a process and give an alternate path by reducing or raising the activation energy between reactants and products, altering the reaction's enthalpy change. As a resu

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct options: A and B

Arrhenius equation k = Ae – $\frac{{\mathbf{E}}_{\mathbf{a}}}{\mathbf{R}\mathbf{T}}$

When the temperature rises, $\frac{{\mathbf{E}}_{\mathbf{a}}}{\mathbf{R}\mathbf{T}}$ value falls and – $\frac{{\mathbf{E}}_{\mathbf{a}}}{\mathbf{R}\mathbf{T}}$

As a result, e- $\frac{{\mathbf{E}}_{\mathbf{a}}}{\mathbf{R}\mathbf{T}}$  increases, and it is certain that k and  T increases as well. As a result, Option A is proven.

Cataly

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Correct options: A and D

According to the graph, the area under the cure must not vary as the temperature rises.T2 > T1

The energy level of T2 is higher than T1.

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Correct options: A and C

The Maxwell Boltzmann distribution, often known as the Gibbs distribution, is a measure that expresses the likelihood of a system being in each state as a function of the energy of that state.

Look at the graph

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Correct options: A and D

Activation Energy is the amount of energy released when reactant molecules collide and form an activated complex. When energy is released, the complex decomposes into a product.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct options: A, C and D

The pressure in this reaction is extremely high, and it becomes independent of the ammonia concentration. The metal surface becomes saturated with gas molecules when the rate of reaction=Rate constant. The