Chemical Kinetics
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Keep it short & simple. Type complete word. Avoid abusive language.
Among the given complexes, number of paramagnetic complexes in__________.
Among the given complexes, number of paramagnetic complexes in__________.
CN is a strong field ligand, so pairing occurs.
1.
So; it is diamagnetic
2.
So; it is paramagnetic.
3.
Ti3+ = 4s03d1
It is paramagnetic
4.
It is diamagnetic
5.
Hence, are paramagnetic.
Spin only magnetic moment of <!-- [if gte mso 9]><xml>
</xml><![endif]-->is________ B.M (round off to the closest integer)
Spin only magnetic moment of <!-- [if gte mso 9]><xml>
40% of HI undergoes decomposition to H2 and I2 at 300K. <!-- [if gte mso 9]><xml>
</xml><![endif]-->for this decomposition reaction at one atmosphere pressure is_____________J mol-1 (nearest integer)
(Use R = 8.31 JK-1 mol-1; log 2= 0.3010, In 10 = 2.3, log 3 = 0.477)
40% of HI undergoes decomposition to H2 and I2 at 300K. <!-- [if gte mso 9]><xml>
(Use R = 8.31 JK-1 mol-1; log 2= 0.3010, In 10 = 2.3, log 3 = 0.477)
The activation energy of one of the reactions is a biochemical process is 532611 J mol-1 when the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10-3 k310. The value of x is___________.
[Given: In 10 = 2.3 R = 8.3 JK-1 mol-1]
The activation energy of one of the reactions is a biochemical process is 532611 J mol-1 when the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10-3 k310. The value of x is___________.
[Given: In 10 = 2.3 R = 8.3 JK-1 mol-1]
Where, K2 is at 310 K and K1 at 300K
K2 = K1 × 103
K1 = K2 × 10-3
x = 1
For a reaction, given below is the graph of ink vs <!-- [if gte mso 9]><xml>
</xml><![endif]--> The activation energy for the reaction is equal to_____________ cal mol-1 (Nearest integer)
(Given: R = 2 cal K-1 mol-1)
For a reaction, given below is the graph of ink vs <!-- [if gte mso 9]><xml>
(Given: R = 2 cal K-1 mol-1)
Comparing with y = mx + c
Slope =
= 8 Cal
For a first order reaction A→B, the rate constant, k = 5.5 × 10-14s-1. The time required for 67% completion of reaction is x × 10-1 times the half life of reaction. The value of x is ________ (Nearest integer)
(Given : log 3 = 0.4771)
For a first order reaction A→B, the rate constant, k = 5.5 × 10-14s-1. The time required for 67% completion of reaction is x × 10-1 times the half life of reaction. The value of x is ________ (Nearest integer)
(Given : log 3 = 0.4771)
Rate constant, k = 5.5 × 10-14 s-1.
=
From (i) & (ii)
= 1.58 t50%
So; t67% is 15.8 × 10-1 times half life.
X = 16 (the ne
The reaction between X and Y is first order respect to X and zero order with respect to Y.
Examine the data of table and calculate ratio of numerical values of M and L (Nearest integer)
The reaction between X and Y is first order respect to X and zero order with respect to Y.
Examine the data of table and calculate ratio of numerical values of M and L (Nearest integer)
According to condition
Rate
By using experimental data I and II
And by using experimental data I and II
M = 8
Ratio of





