Chemistry NCERT Exemplar Solutions Class 11th Chapter Nine

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a month ago

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R
Raj Pandey

Contributor-Level 9

eq of H? O? = eq of KMnO?
(0.316 / 158) x 5 = 0.01
(0.01 x 17 / 0.2) x 100 = 85%

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

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a month ago

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R
Raj Pandey

Contributor-Level 9

N? + 3H? → 2NH?
(2.8 x 10³) / 28 → 0.1 x 10³ mol LR
(1 x 10³) / 2 → 0.5 x 10³ mol

Mass of NH? produced = 0.2 * 10³ * 17 = 3.4 kg = 3400 g

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a month ago

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R
Raj Pandey

Contributor-Level 9

first order reaction
K = (2.303/t) log (a? / (a? - x)
K = (2.303/90) log (a? / 0.25a? ) = 0.0154
t = 60% = (2.303/K) log (a? / a? ) . (2)
= (2.303 / 0.0154) x (1 - 0.602) = 59.51 mins ≈ 60

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a month ago

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R
Raj Pandey

Contributor-Level 9

P? = X? (P? – P? ) + P?
ATQ
550 = 1/4 (P? – P? ) + P?
2200 = P? – P? + 4P?
560 = 1/5 (P? – P? ) + P?
2200 = P? – P? + 5P?
P? + 3P? = 2200
P? + 4P? = 2800
P? = 600
P? = 400 mmHg

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