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New answer posted
a month agoContributor-Level 10
There are multiple factors that make the carbonyl group a strong ligand. Check the list below for the reasons.
- Unlike other alkyl ligands, it is an unsaturated compound.
- Due to its unsaturated nature, it has difficulty donating? electron density.
- It has a tendency to accept? (Pie) antibonding electrons.
- CO ligand acts as Lewis acid and donates a lone pair of electrons to form a metal-carbon bond.
- The? -acidic nature of CO gives a strong field and greater d-orbital splitting.
New answer posted
a month agoContributor-Level 10
Relative lowering in vapour pressure depends on no. of mole of solute greater the no. of mole of solute greater in RLVP and smaller will be vapour pressure. So order of vapour pressure is B > C > A.
New answer posted
a month agoContributor-Level 10
Π = iCRT = I (n/V)RT
Πfinal = (Π? V? + Π? V? )/ (V? + V? )
Πfinal = [ (0.1 * 1) + (0.2 * 2)]/3
= (0.1 + 0.4)/3 = 0.5/3 = (500/3) * 10? ³ atm
so X = 167
New answer posted
a month agoContributor-Level 10
Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10
New answer posted
a month agoContributor-Level 9
P? = X? (P? – P? ) + P?
ATQ
550 = 1/4 (P? – P? ) + P?
2200 = P? – P? + 4P?
560 = 1/5 (P? – P? ) + P?
2200 = P? – P? + 5P?
P? + 3P? = 2200
P? + 4P? = 2800
P? = 600
P? = 400 mmHg
New answer posted
a month agoContributor-Level 10
At equivalence point is 7 and increases with addition of so correct graph is (1).
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