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New answer posted
4 months agoContributor-Level 10
Π = iCRT = I (n/V)RT
Πfinal = (Π? V? + Π? V? )/ (V? + V? )
Πfinal = [ (0.1 * 1) + (0.2 * 2)]/3
= (0.1 + 0.4)/3 = 0.5/3 = (500/3) * 10? ³ atm
so X = 167
New answer posted
4 months agoContributor-Level 10
Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10
New answer posted
4 months agoContributor-Level 9
P? = X? (P? – P? ) + P?
ATQ
550 = 1/4 (P? – P? ) + P?
2200 = P? – P? + 4P?
560 = 1/5 (P? – P? ) + P?
2200 = P? – P? + 5P?
P? + 3P? = 2200
P? + 4P? = 2800
P? = 600
P? = 400 mmHg
New answer posted
4 months agoContributor-Level 10
At equivalence point is 7 and increases with addition of so correct graph is (1).
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