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New answer posted
2 months agoContributor-Level 10
All the solution have higher ion production with respect to 0.1 M C2H5OH i.e. 0.1 M Ba3 (PO4)2, 0.1 M Na2SO4, 0.1 M KCl and 0.1 M Li3PO4. Hence all have lowered freezing point than 0.1 M C2H5OH (which is non-ionisable in aqueous medium).
Ans. = 4
New answer posted
2 months agoContributor-Level 10
{for ethylene glycol I = 1, due to non-ionisable}
(the nearest integer)
Hence, freezing point of solution = 273 K – 4K = 269 K.
New answer posted
2 months agoContributor-Level 10
Molality itself a strength representing terms for solution which does not depend upon the temperature.
New answer posted
2 months agoContributor-Level 10
Let we take of solution
Mass of solute = Volume * Density
= 0.5
= 0.525 gram
Mass of solution = 1 kg. [considering very dilute solution]
Mass of solvent = 1000 – 0.525 = 999.475 gram
New answer posted
2 months agoContributor-Level 10
For A : 100 gm solution 2 gm solute A
For B : 100 gm solution 8 gm solute B
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