Chemistry
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New answer posted
a year agoContributor-Level 9
eq of H? O? = eq of KMnO?
(0.316 / 158) x 5 = 0.01
(0.01 x 17 / 0.2) x 100 = 85%
New answer posted
a year agoContributor-Level 10
Π = iCRT = I (n/V)RT
Πfinal = (Π? V? + Π? V? )/ (V? + V? )
Πfinal = [ (0.1 * 1) + (0.2 * 2)]/3
= (0.1 + 0.4)/3 = 0.5/3 = (500/3) * 10? ³ atm
so X = 167
New answer posted
a year agoContributor-Level 10
Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10
New answer posted
a year agoContributor-Level 10
(i) 2Fe²? + H? O? → 2Fe³? + 2OH?
(ii) 2MnO? + 5H? O? + 6H? → 2Mn²? + 5O? + 8H? O
So sum of (x + y + x¹ + y¹ + z¹) = 2 + 2 + 2 + 5 + 8 = 19
New answer posted
a year agoContributor-Level 10
k = Ae? Ea/RT
ln (K? /K? ) = (Ea/R) [1/T? - 1/T? ]
ln (5) = (Ea/8.314) [1/300 - 1/315]
1.6094 = (Ea/8.314) [15 / (300 * 315)]
Ea = 84297 J
New answer posted
a year agoContributor-Level 10
For hydrogen atom :
For Lyman series n? = 1 & n? = ∞
1/λH = RH [1/1² - 1/∞²] So, λ = 1/RH
For He? ion Balmer series n? = 2 & n? = 3
1/λHe? = RH * Z² [1/n? ² - 1/n? ²]
1/λHe? = RH * 4 * [1/4 - 1/9] = RH * 4 * (5/36)
1/λHe? = (5/9)RH = (5/9) (1/λ)
(λHe? ) = (9/5)λ
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