Chemistry

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New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

log (k? /k? ) = (Ea / 2.303R) [1/T? - 1/T? ]
log (3.555) = (Ea / (2.303R) [1/303 - 1/313]
1.268 * 8.314 * 303 * 313 = 10Ea
So, Ea = 100 kJ

New answer posted

10 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

According to IUPAC convention for naming of elements with atomic number more than 100, different digits are written in order and at the end ium is added. For digits following naming is used.

0 -nil

1-un

2-bi

3-tri

and so on.

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 * 10?

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution

 

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Misch metal consists of Lanthanide metal (? 95%) and iron (? 5%) and traces of S, C, Ca and Al.

New answer posted

10 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Na? SO? + H? SO? → SO? + Na? SO? + H? O
SO? + 2NaOH → Na? SO? + H? O
Na? SO? + SO? + H? O → 2NaHSO?

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

For concentration cell E? cell = 0
Anode: Cu (s) → Cu²? (aq)?
Cathode: Cu²? (aq)? → Cu (s)
Overall: Cu²? (aq)? → Cu²? (aq)?
As ΔG = −nFEcell
If ΔG = -ve than Ecell is positive
Ecell = E? cell − (0.059/2) log (C? /C? )
Ecell = − (0.059/2) log (C? /C? )
Ecell > 0 ⇒ C? > C?

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