Chemistry

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A
alok kumar singh

Contributor-Level 10

Dihydrogen of high degree of purity (>99.95%) is obtained by the electrolysis of warm aqueous barium hydroxide solution between nickel electrodes.

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Satyendra Dhyani

Beginner-Level 5

The metal-carbon bonds (M-C) in metal carbonyls are due to the synergic interaction between the metal and carbonyl group. There are two types of bonding between metal and carbonyl group. 

? -bond in Metal Carbonyls: The Carbonyl (CO) ligand donates a lone pair of electrons to the metal center to fill its empty d-filled orbital. This electron density donation is called? -donation.

? -back bond in Metal Carbonyls: This is the case of back bonding. The already filled d-orbitals return the electron density into the empty? * (antibonding) orbital of CO. This electron density donation by the metal is called? -back donation.

Both these comb

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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10 months ago

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A
alok kumar singh

Contributor-Level 10

³? Cl ³? Cl
Molar ratio x 1 – x
M? 35 * x + 37 (1 − x) = 35.5
35x + 37 – 37x = 35.5
2x = 1.5
x = 3/4
So, ratio of ³? Cl: ³? Cl = 3: 1

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A
alok kumar singh

Contributor-Level 10

For oxide to be stable its ΔG value should be negative.

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R
Raj Pandey

Contributor-Level 9

eq of H? O? = eq of KMnO?
(0.316 / 158) x 5 = 0.01
(0.01 x 17 / 0.2) x 100 = 85%

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10 months ago

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V
Vishal Baghel

Contributor-Level 10

Π = iCRT = I (n/V)RT
Πfinal = (Π? V? + Π? V? )/ (V? + V? )
Πfinal = [ (0.1 * 1) + (0.2 * 2)]/3
= (0.1 + 0.4)/3 = 0.5/3 = (500/3) * 10? ³ atm
so X = 167

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10 months ago

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V
Vishal Baghel

Contributor-Level 10

Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10

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