Chemistry

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New answer posted

7 months ago

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R
Raj Pandey

Contributor-Level 9

Z = 101 belong to actinoids
104 belong to group 4

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

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V
Vishal Baghel

Contributor-Level 10

S 1 reaction depends on carbocation stability and cation form in 3 will be most stable.

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V
Vishal Baghel

Contributor-Level 10

On adding reaction equilibrium constant will get multiplied.

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Vishal Baghel

Contributor-Level 10

H can easily gain electron to form its anion.

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Raj Pandey

Contributor-Level 9

4Li + O? → 2Li? O oxide
2Na + O? → Na? O? peroxide
K + O? → KO? superoxide

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V
Vishal Baghel

Contributor-Level 10

Due to resonance C – Cl bond in option B is the shortest.

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V
Vishal Baghel

Contributor-Level 10

Charge (q) = (it/96500) F = (1x15x60)/96500 = 900/96500 = 9/965 F = 0.0093F
No. of moles of Au? = 0.025 & No. of moles of Ag? = 0.025
Species with higher value of SRP will get deposited first at cathode.
(i) Au? (aqs) + e? → Au (s)
0.025 0.0093 mole
So only Au will get deposited

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