Chemistry

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4 months ago

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R
Raj Pandey

Contributor-Level 9

In presence of sunlight CFC's molecule divides & release chlorine free radical, which react with ozone give chlorine monoxide radical (CIO°) and oxygen.
CF? Cl? (g) → C (g) + C? Cl (g)
Cl° (g) + O? (g) → ClO° (g) + O? (g)
ClO° (g) + O (g) → Cl° (g) + O? (g)

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Raj Pandey

Contributor-Level 9

Reaction path is SN2 because OH? is strong nucleophile, but hydroxyl ion will not attack on chiral centres and so there is retension of configuration.

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4 months ago

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Vishal Baghel

Contributor-Level 10

P? V? =P? V? 48*10? ³*3³ = P? *12³. P? =750*10?

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Vishal Baghel

Contributor-Level 10

i of CaCl? =3. Molality eff=0.15. Molality eff of complex=0.3. [Cr (NH? )? Cl]Cl?

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Raj Pandey

Contributor-Level 9

Mole of Bromine = 0.08/80 = 10? ³ mole
Molar mass of compound = 0.172/M = 10? ³
M = 0.172/10? ³ = 172g
Molar mass of

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Vishal Baghel

Contributor-Level 10

n (KClO? )=10/122. No. of F = (10/122)*6. No. of F supplied= (100/122). t=11hrs.

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Vishal Baghel

Contributor-Level 10

AgBr=1.88g. Br=0.8g. %Br= (0.8/1.6)*100=50%.

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

rate=k [Conc]? log [rate]=logk+nlog [Conc]. 'n' is slope. Higher slope, higher order.

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