Chemistry

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New answer posted

10 months ago

0 Follower 4 Views

A
Aadit Singh Uppal

Contributor-Level 10

These are the important highlights of integrated rate equations:

  • predict the rate of a reaction
  • calculate order of reaction (zero, first, second)
  • understand mechanism of a reaction
  • compute half life
  • calculate the value of k

New answer posted

10 months ago

0 Follower 1 View

A
Aadit Singh Uppal

Contributor-Level 10

Yes, the phase of the reactant (solid, liquid or gas) actually affects the rate of a reaction. Gases and Liquids tend to move more freely and effectively as compared to solids, which increaes the frequency of particles colliding with each other.

New answer posted

10 months ago

0 Follower 6 Views

A
Aadit Singh Uppal

Contributor-Level 10

This is possible because these catalysts have a lower activation energy, which allows a comparatively higher number of particles to react at a faster rate. More number of particles will mean more frequent collisions which speeds up the process.

New answer posted

10 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

16.00
X + Y? 2Z
Initial 1.0 1.5 0.5
At equ m 1-x 1.5-x 0.5+2x
equ m conc 0.75 1.25 1.0
0.5 + 2x = 1
x = 0.25
K = 1 / (0.75 * 1.25)
K = 16/15
x = 16.00

New answer posted

10 months ago

0 Follower 49 Views

V
Vishal Baghel

Contributor-Level 10

50.00
K? Cr? O? + FeC? O? → Fe³? + CO? + Cr³? + K? + H? O
n_f=6    n_f=3
Now apply equivalent concept
0.02 * 6 * V = (0.288 / (144/3) * 10³
Normality
V = (0.288 * 10³)/ (48 * 6 * 0.02) = 50.00 mL

New answer posted

10 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

13.49
2 A (g) → A? (g)
Δn_g = 1 - 2
Δn_g = 1
ΔH = ΔU + Δn_gRT
ΔH = -20 * 10³ + (-1)8.31 * 298
ΔH = -22477.572 J mol? ¹
ΔG = ΔH - TΔS
ΔG = -22477.572 - (-30)298 = -22477.572 + 8940
ΔG = -13537.57 J mol? ¹

New answer posted

10 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Δ? > P
Pairing of electron will take place


Number of unpaired electron = 0
µ = 0.00

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

9.00

α - D - Glucose sucrose β – D - Fructose

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

(A) Trans

(B) Cis

Optically inactive due to presence of plane of symmetry

Optically active no plane of symmetry

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Boiling and clark's method (Ca (OH)? ) are used for removing temporary hardness. Whereas, calgon, sodium carbonate ion exchange method are used for removing permanent hardness.

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