Chemistry

Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry

Follow Ask Question
6.9k

Questions

0

Discussions

28

Active Users

0

Followers

New answer posted

7 months ago

0 Follower 26 Views

R
Raj Pandey

Contributor-Level 9

48.00

| w | = 1 2 ( 6 + 10 ) = 48 J

New answer posted

7 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

1.52

E = E 0 - 0.0591 4 l o g ? H + 4

E = 1.23 + 0.0591 * p H

E = 1.23 + 0.0591 * ( 5 )

E = 1.52

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

7 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

C o N H 3 6 C l 3 + 3 A g N O 3 ? 3 A g C l

  Mole of   C o N H 3 6 C l 3 1 =   Mole of   A g N O 3 3

0.3 267.46 = 0.125 * V * 10 - 3 3

V = 26.92 m L

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Order of I.E:           N a < A l < M g < S i

496 577 737 786

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Number of bond between sulphur and oxygen = 8

Number of bond between sulphur and sulphur = 8

New answer posted

7 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

v = 1 λ = R z 2 ? 1 n 1 2 - 1 n 2 2

For H atom z = 1

v = R 1 n 1 2 - 1 n 2 2

For Balmer series:  n 1 = 2

If n 2 = 3 1 λ = R z 2 1 4 - 1 9

1 λ = R 5 36

λ m a x = 36 5 R

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Aq. N a O H  in a burette and aqueous oxalic acid in a conical flask.

New answer posted

7 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

Without catalyst: K = A e - E a / R T

  Presence catalyst:   10 6 K = A e - E c / R T E q ( B ) - E q ( A ) 10 6 = e - ( E - E c ) / R T E - E c R T = 2.303 * 6 Δ E = E c - E = ( - 2.303 ) * 6 R T

New answer posted

7 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

X Y 2 X + 2 + 2 y - K   sp   = X + 2 [ X ] 2 = 10 - 3 2 * 10 - 3 2 = 4 * 10 - 9

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.