Chemistry
Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
10 months agoContributor-Level 9
At a fixed temperature, having more vapour pressure as compared to . So, intermolecular interaction is lower as compared to .
New question posted
10 months agoNew answer posted
10 months agoContributor-Level 10
In a hydrogen atom, which we know has a single electron, the orbital energy will only depend on the principal quantum number (n). Here, the orbitals like 2s and 2p have the same energy (degenerate).
It's a little different with multielectron atoms. The energy depends on both n and the azimuthal quantum number (l). This causes splitting. And, the energies increase in the order: s < p < d < f.
New answer posted
10 months agoContributor-Level 10
The quantum mechanical model of the atom is a significant shift from orbits to orbitals. Though Bohr's atomic model was the beginning of understanding of how electrons move in fixed circular paths, it was Heisenberg's Uncertainty Principle that changed the view. It showed exact positions and velocities can't both be known. So definite orbits don't exist.
In the quantum mechanical model of atom, electrons are treated as waves and described by orbitals. These are regions where they are most likely to be found. These come from Schrödinger's wave function, where |? |² gives the probability of locating an electron. Each orbital is defined
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 702k Reviews
- 1850k Answers



