Chemistry

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New answer posted

a year ago

0 Follower 33 Views

R
Raj Pandey

Contributor-Level 9

48.00

| w | = 1 2 ( 6 + 10 ) = 48 J

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

1.52

E = E 0 - 0.0591 4 l o g ? H + 4

E = 1.23 + 0.0591 * p H

E = 1.23 + 0.0591 * ( 5 )

E = 1.52

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

a year ago

0 Follower 15 Views

R
Raj Pandey

Contributor-Level 9

C o N H 3 6 C l 3 + 3 A g N O 3 ? 3 A g C l

  Mole of   C o N H 3 6 C l 3 1 =   Mole of   A g N O 3 3

0.3 267.46 = 0.125 * V * 10 - 3 3

V = 26.92 m L

New answer posted

a year ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Order of I.E:           N a < A l < M g < S i

496 577 737 786

New answer posted

a year ago

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R
Raj Pandey

Contributor-Level 9

Number of bond between sulphur and oxygen = 8

Number of bond between sulphur and sulphur = 8

New answer posted

a year ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

v ‾ = 1 λ = R z 2 ? 1 n 1 2 - 1 n 2 2

For H atom z = 1

v ‾ = R 1 n 1 2 - 1 n 2 2

For Balmer series:  n 1 = 2

If n 2 = 3 ∴ 1 λ = R z 2 1 4 - 1 9

1 λ = R 5 36

λ m a x = 36 5 R

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Aq. N a O H  in a burette and aqueous oxalic acid in a conical flask.

New answer posted

a year ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

Without catalyst: K = A e - E a / R T

  Presence catalyst:   10 6 K = A e - E c / R T E q ( B ) - E q ( A ) 10 6 = e - ( E - E c ) / R T E - E c R T = 2.303 * 6 Δ E = E c - E = ( - 2.303 ) * 6 R T

New answer posted

a year ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

X Y 2 → X + 2 + 2 y - K   sp   = X + 2 [ X ] 2 = 10 - 3 2 * 10 - 3 2 = 4 * 10 - 9

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