Chemistry

For first order reaction, using

$K=\frac{2.303}{t}lo{g}_{10}\frac{{\left[R\right]}_0}{\left[R\right]}$              

$K=\frac{2.303}{60}\left(0.477-0.301\right)mi{n}^{-1}$              

$K=6.7*10^{-3}mi{n}^{-1}$              

Ans. is 7 (the nearest integer)

NH₃ behaves as strong field ligand with Co²⁺ & Co³⁺

$\left[Co{\left(N{H}_3\right)}_6\right]C{l}_2$              

$C{o}^{2+}-4s^{0}3d^7$      

It has one unpaired electorn.

 $\left[Co{\left(N{H}_3\right)}_6\right]C{l}_3$

$C{o}^{3+}-4s^{0}3d^6$    

It has no unpaired electrons

So, total unpaired electrons in both compounds is 1.

Reduced pressure distillation technique is used for purification of high boiling organic liquid which decompose near its boiling point. By reducing pressure they boil below their normal boiling point.

Solubility of gas in liquid increases on decreasing the temperature. So water at 4°C will have more dissolved O₂.

Aniline being a base does not give Friedel Craft reaction because it react with AlCl₃ used in Friedel Craft reaction.

Vitamin B₁ is thiamine while vitamin B₆ is pyridoxine

Reducing power for group-15 hydrides increases down the group, so BiH₃ is the strongest reducing agent.