Chemistry

Kl acts as a reducing agent for $C{u}^{2+}\left[2C{u}^{++}+4Kl\to C{u}_2{l}_2+l_2+4K^{+}\right]$

In strong field of octahedral complex of Fe²⁺, the electronic configuration is,

$F{e}_{26}^{2+}\to \left[Ar\right]3d^{6}4s^0$

Number of unpaired electrons are zero in the presence of strong field ligand.

Hence, spin only magnetic moment = $\sqrt[]{n\left(n+2\right)}=0BM\left(n=0\right)$

High leaving tendency corresponds to high reactivity towards hydrolysis. Hence order is.

Anhydride of HNO₃ produced by the treatment of P₄O₁₀ (anhydring reagent) in ratio of 4 : 1 is N₂O₅ which is acidic in nature. $4HN{O}_3+P_4{O}_{10}\to \underset{Acidicnature}{\underset{?}{2N_2{O}_5}}+{\left(HP{O}_3\right)}_4$

Calcinations is the decomposition in absence of air, $ZnC{O}_3\underset{\Delta }{\overset{}{\to }}ZnO+C{O}_2\uparrow$ ${}_{}\underset{}{\overset{}{}}{}_{}$

while roasting is the oxidation process, $2ZnS+3O_2\to 2ZnO+2S{O}_2\uparrow$

Bakelite is cross linked polymer of formaldehyde and novolac. Novolac is linear polymer of phenol-formaldehyde.

Kindly consider the following figure

Given electronic configuration is for Ga and in 5^th period diagonally situated element is Sn with respect to Ga. Hence electronic configuration of Sn is [Kr]4d¹⁰5s²5p².

Mechanism path is free radical.

Conductivity;    $\kappa =1.07*10^{6}S{m}^{-1}$

Resistance ; R = 0.243    $\Omega$

cell constant ; G^* =?

Using ;

$\kappa =\frac{G^{*}}{R}$      

$G*=\kappa *R$          

$=1.07*10^6*0.243m^{-1}$                

$=26*10^4{m}^{-1}$