Chemistry

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New answer posted

7 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Structure (I) is anti conformer.

Structure (II) is fully eclipsed conformer.

Structure (III) is skew or gauche conformer.

Structure (IV) is partially eclipsed.

order of stability

(I) > (III) > (IV) > (II)

Order of P.E. is (II) > (IV) > (III) > (I).

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Na/H2 can not reduce a functional group as Na does not behaves as catalyst here.

New answer posted

7 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Stability order of oxides (X2O) is,

l2O > Cl2O > Br2O

Bonds of halogen & oxygen are covalent due to less EN difference.

Stability of (I - O) bond is higher due to less polarity and that of (Cl-O) bond is higher due to multiple bonding.

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(a) Cell constant = ( l A ) = m / m 2 = m 1  

(b) molar conductivity ( λ m ) = κ * 1 0 0 0 m o l a r i t y

= Scm2 mol-1

(c) Conductivity ( κ ) = 1 ρ = l R A

= Ω 1 m 1                                

(d) degree of dissociation = n u m b e r o f m o l e d i s s o c i a t e d T o t a l m o l e , it is dimensionless 

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Ethylene glycol (HO – CH2 – CH2 – OH) and terephthalic acid

 

New answer posted

7 months ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

Rate constant depends on temperature as

K = A e E a / R T              

Here; as T increases rate constant increases exponentially.

New answer posted

7 months ago

0 Follower 47 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

In reaction ;

  5 F e 2 + + M n O 4 + 8 H + M n 2 + + 4 H 2 O + 5 F e 3 +              

Colour of Fe2+ is green and that of Fe3+ is yellow.

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

l n [ C o ( C N ) 6 ] 4 , Co has +2 oxidation state

Hence, electronic configuration of CO2+ is [ A r ] 3 d 7 4 s 0  . In complex   [ C o ( C N ) 6 ] 4 , given ligand CN is strong hence, after pairing in d-subshell, total number of unpaired electron =

spin magnetic moment =   1 ( 1 + 2 ) = 3 = 1 . 7 3 B M

= 1 . 7 3 B M 2 . 0 B M

 

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly conside the following Image

 

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