Chemistry

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4 months ago

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A
alok kumar singh

Contributor-Level 10

[ N H 4 C l ] = 2 6 0 = 1 3 0 M

p H = 7 1 2 P K b 1 2 l o g C

= 7 5 2 1 2 l o g ( 1 3 0 ) = 5 . 2 4

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Let we take  1 l  of solution

Mass of solute = Volume * Density

= 0.5  m l * 1 . 0 5 g m / m l  

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

i = 1 . 9  

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4 months ago

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Payal Gupta

Contributor-Level 10

Ce3+ [Xe]4f15d0

Ce4+ [Xe]4f05d0  (Noble gas configuration)

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Payal Gupta

Contributor-Level 10

Disproportionation reaction is

Mg+6O4+4H+2Mn+7O4+Mn+4O2+2H2O

New answer posted

4 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

Value of n &  l can't be same

New answer posted

4 months ago

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Payal Gupta

Contributor-Level 10

Kindly consider the below image

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Let a moles of SO2Cl2 is taken

Then no. of moles of H2SO4 = a moles

No. of moles of HCl = 2a moles

No. of moles of NaOH required = 2a + 2a = 4a = 16

 

New question posted

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New answer posted

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P
Payal Gupta

Contributor-Level 10

During removal of temporary hardness of water.

Mg (HCO3)2BoilMg (OH)2+2CO2Ca (HCO3)2BoilCaCO3+H2O+CO2

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

B2H6 has 4 2 c -2e bonds and 2 3c-2e bonds.

Bridging (B-H) bonds have more value of bond- length then terminal (B – H) bonds

Bridging bonds are in one plane, but terminal bonds are in perpendicular plane.

Due to presence of (3c-2e) bonds, it behaves as electrons deficient and prone to get attached by  lewis      base.

3 N a B H 4 + 4 B F 3 ? ? 3 N a B F 4 + 2 B 2 H 6

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