Chemistry

All structure can produce -CHO functional group which gives +ve test of Tollen's reagent except structure (II), because if forms ketonic group after tautomerisation

$X\underset{H_{2}S{O}_4}{\overset{Conc}{\to }}$ Brown fumes + Brown ring test with FeSO₄/H₂SO₄

$x\underset{HCl}{\overset{H_{2}S}{\to }}Y\left(ppt\right)\underset{HN{O}_3}{\overset{Conc}{\to }}dissolved\underset{N{H}_{4}OH}{\overset{}{\to }}$ Deep blue colour solution

In cation analysis of Cu⁺ ions, precipitate formed is CuS on treating with H₂S and HCl which dissolved in HNO₃ and produced blue colour complex solution ${\left[Cu{\left(N{H}_3\right)}_4\right]}^{++}$ in NH₄OH. Brown fumes and brown ring performance given by nitrate sample. Hence salt is Cu (NO₃)₂.

In $Br{O}_4^{-},Br$ has +7 O.S, therefore it only acts as a oxidizing reagent, does not undergo disproportionation reaction

$6O{H}^{-}+C{l}^{-}\to Cl{O}_3^{-}+3H_{2}O+6e^{-}$

Mole of  $Cl{O}_3^{-}orKCl{O}_3=\frac{10}{122.6}=0.8456mol$

1 mole of $Cl{O}_3^{-}$  or KClO₃ produced by 6 faraday (F).

$\therefore 0.08456$ mole of $Cl{O}_3^{-}$ or KClO₃ produced by (6 * 0.08156) F

$\frac{l*t}{F}=6*0.8156$

$l=\frac{6*0.08156*965000}{10*60*60}A=1.311A\approx 1A$

$PC{l}_5\left(g\right)\to PC{l}_3\left(g\right)+C{l}_2\left(g\right)$ (first order reaction)

$K=\frac{2.303}{120}log\left(\frac{50}{10}\right)$      

$\therefore K=\frac{2.303*log5}{120min}=\frac{2.303*0.6989}{120}$ = 0.0134 min^-1

Rate constant at 300K = 1.34 * 10^-2min^-1 [the nearest integer = 1.0]

Total pressure of mixture =   $P_{Total}=X_A*P_A^o+X_B*P_B^o=90*0.6+15*0.4=60mm$

Mole fraction of B in vapour phase, $\left(X_B^{\text{'}}\right)=\frac{X_B*P_B^o}{P_{Total}}$

$\therefore X_B^{\text{'}}=\frac{0.4*15}{60}=0.1=1*10^{-1}$  

In fcc structure of diamond four C present in fcc lattice and other four C present in tetrahedral voids where 50% of tetrahedral voids are occupied. Hence number of carbon atoms present per unit cell of diamond is 8.

$NiC{l}_2+NaCN\underset{O.A.}{\overset{strong}{\to }}{\left[Ni{\left(CN\right)}_6\right]}^{2-}$

Complex has Ni⁴⁺ and strong ligand, hence following are the metal ion electronic configuration

Change of unpaired electron = 2