Chemistry
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New answer posted
4 months agoContributor-Level 10
Let we take of solution
Mass of solute = Volume * Density
= 0.5
= 0.525 gram
Mass of solution = 1 kg. [considering very dilute solution]
Mass of solvent = 1000 – 0.525 = 999.475 gram
New answer posted
4 months agoContributor-Level 10
Let a moles of SO2Cl2 is taken
Then no. of moles of H2SO4 = a moles
No. of moles of HCl = 2a moles
No. of moles of NaOH required = 2a + 2a = 4a = 16
New question posted
4 months agoNew answer posted
4 months agoContributor-Level 10
B2H6 has 4 2 c -2e bonds and 2 3c-2e bonds.
Bridging (B-H) bonds have more value of bond- length then terminal (B – H) bonds
Bridging bonds are in one plane, but terminal bonds are in perpendicular plane.
Due to presence of (3c-2e) bonds, it behaves as electrons deficient and prone to get attached by lewis base.
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