Chemistry

When AgNO₃ is added to Kl solution, precipitate of Agl is formed which adsorb I^- ion from

Dispersion medium to give negatively charged sol

$AgN{O}_3+Kl\to Agl\downarrow +KN{O}_3$

Agl/l^-- negatively charged sol.

Esters on treating with excess CH₃MgBr followed by hydrolysis gives 3° alcohol.

 

Electronic configuration of Ga⁺ ion = [Ar] 3d¹⁰ 4s² 4p⁰

Last electron goes into S-orbital, hence

Azimuthal quantum number $\left(\mathcal{l}\right)$ for last electron = 0

Kt = 2.303 log $\frac{\left[A_0\right]}{\left[A_t\right]}$  

Here, $\left[A_0\right]=100,\left[A_t\right]=90andt=1min$  

$\therefore K*1=2.303lo{g}_{10}\frac{100}{90}$

$\therefore K=2.303\left[1-2*0.477\right]=0.105938=105.938*10^{-3}mi{n}^{-1}$                             

Rounded = 106

Reaction of acetone and semicarbazide

$P_B^O=$ vapour pressure of benzene at 20°C = 70 torr

$P_M^O$ = vapour pressure of toluene at 20°C = 20 torr

Mixture is equimolar, X_B = 0.5 and X_M = 0.5

Total vapour pressure (P_T) = 70 * 0.5 + 20 * 0.5 = 45 torr

Mole fraction of benzene in vapour phase $\left(x_B^{\text{'}}\right)=\frac{P_B^O{X}_B}{P_T}=\left(\frac{70*0.5}{45}\right)torr$

= 0.777 = 77.7 * 10^-2 torr

Ans. = 78 (the nearest integer)

Hence, electronic configuration of CO²⁺ is $\left[Ar\right]3d^{7}4s^0$ . In complex ${\left[Co{\left(CN\right)}_6\right]}^{4-},$ given ligand CN^- is $\therefore$ strong hence, after pairing in d-subshell, total number of unpaired electron =

spin magnetic moment = $\sqrt[]{1\left(1+2\right)}=\sqrt[]{3}=1.73BM$ $=1.73BM\approx 2.0BM$  

For Ni²⁺, crystal field CFSE magnitude shows the magnitude of absorbed light. Following are the energy absorbed order

  ${\left[NiC{l}_4\right]}^{2-}<{\left[Ni\left(H_{2}O\right)\right]}^{2+}<{\left[Ni{\left(CN\right)}_4\right]}^{2-}$

Hence order of colour of compounds are.

${\left[NiC{l}_4\right]}^{2-}>{\left[Ni{\left(H_{2}O\right)}_6\right]}^{2+}>{\left[Ni{\left(CN\right)}_4\right]}^{2-}$