Chemistry

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New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

[ N H 4 C l ] = 2 6 0 = 1 3 0 M

p H = 7 1 2 P K b 1 2 l o g C

= 7 5 2 1 2 l o g ( 1 3 0 ) = 5 . 2 4

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Let we take  of solution

Mass of solute = Volume * Density

= 0.5 m l * 1 . 0 5 g m / m l

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

i = 1 . 9

 

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Value of n & l  can't be same

New answer posted

11 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

New answer posted

11 months ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

XeO3sp3, Pyramidal

XeF2 sp3d2, square pyramidal

XeF6 sp3d3, Distorted octahedral

XeOF4 sp3d2, square pyramidal

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

S O 2 C l 2 + 2 H 2 O H 2 S O 4 + 2 H C l

Let a moles of SO2Cl2 is taken

Then no. of moles of H2SO4 = a moles

No. of moles of HCl = 2a moles

No. of moles of NaOH required = 2a + 2a = 4a = 16

a = 4 m o l e s

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

(A) Sulphate (>500 ppm) ® causes laxative effect that leads to dehydration.

(B) Nitrate (> 50 ppm) ® causes methemoglobinemia, skin appears blue.

(C) Lead (>50 ppb) ® It damage kidney and RBC.

(D) Fluoride (>2ppm) ® It causes brown mottling of teeth.

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

Number of Mn = O bonds = 6

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

Neutral KMnO4 oxidises I- to  and magnate ion has dpPp bonding

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

Pyrophosphorous acid = H4P2O5

 Hypophosphorous acid = H4P2O6

 Phosphoric acid = H3PO4

 Pyrophosphoric acid = H4P2O7

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