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Chemistry Structure of Atom

Given below are two statements. One is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Energy of 2s orbital of hydrogen atom is greater that that of 2s orbital of lithium.

Reason R: Energies of the orbitals in the same subshell decrease with increase in the atomic.

In the light of the above statements, choose the correct answer from the options given below:

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alok kumar singh

Contributor-Level 10

Energy of orbitals in same subshell decrease on increasing the atomic number.

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Chemistry Class 12th

Given below are two statements.

Statement I: O₂, Cu²⁺, and Fe³⁺ are weakly attracted by magnetic field and are magnetized in the same direction as magnetic field.

Statement II: NaCl and H₂O are weakly magnetized in opposite direction to magnetic field.

In the light of the above statements, choose the most appropriate answer from the options given below.

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alok kumar singh

Contributor-Level 10

$O_{2}, C u^{2 +} a n d F e^{3 +}$

are paramagnetic

$∴$ Weakly attracted by magnetic field

NaCl and H2O are diamagnetic

$∴$ Weakly repelled by magnetic field.

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Chemistry Class 12th

250g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to

(Given : Atomic weights are, H, 1u ; C, 12u ; O, 16u)

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alok kumar singh

Contributor-Level 10

$C_{6} H_{12} O_{6} \to G l u c o s e$

$\frac{M a s s o f C}{m a s s o f g l u c o s e} = \frac{72}{180}$

% of C = 10.8 = $\frac{M a s s o f C}{m a s s o f s o l u t i o n} * 100$

$\frac{10.8 * 250}{100} m a s s o f C$

$∴ M o l a r i t y = \frac{0.375}{0.1825} = 2.055 = 2.06$

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Chemistry Bond Parameters

Explain why the bond angle in ${N H}_{3}$ is larger than in ${P H}_{3}$ ?

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Himanshi Singh

Beginner-Level 5

The reason why bond angle is larger in ${N H}_{3}$ than ${P H}_{3}$ are given below.

In ${N H}_{3}$ , there is one lone pair on the nitrogen atom increases repulsion, while the lone pair on phosphorus is in a higher energy orbital and causes less repulsion.
Nitrogen is a small and electronegative atom whereas phosphorus is larger and less electronegative than nitrogen.
In ${P H}_{3}$ , the bonding orbitals are nearly pure p-orbitals, which are less directionals–p hybridization, on the other hand, the bond pairs remain fairly directed, leading to a larger bond angle.

Hence, the bond angle in ${N H}_{3}$ is about 107° ( less than the ideal tetrahedral 109.5°) due to lone pair pres

...more

The reason why bond angle is larger in ${N H}_{3}$ than ${P H}_{3}$ are given below.

In ${N H}_{3}$ , there is one lone pair on the nitrogen atom increases repulsion, while the lone pair on phosphorus is in a higher energy orbital and causes less repulsion.
Nitrogen is a small and electronegative atom whereas phosphorus is larger and less electronegative than nitrogen.
In ${P H}_{3}$ , the bonding orbitals are nearly pure p-orbitals, which are less directionals–p hybridization, on the other hand, the bond pairs remain fairly directed, leading to a larger bond angle.

Hence, the bond angle in ${N H}_{3}$ is about 107° ( less than the ideal tetrahedral 109.5°) due to lone pair presence and highly electronegative atom, and the bond angle in PH? ( 93.5°) is much smaller due to less repulsive lone pair, and less electronegative atom.

Hence, the bond angle in ${N H}_{3}$ (107°) is larger than in ${P H}_{3}$ (93.5°).

less

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Chemistry Bond Parameters

Why the bond length in NO? is shorter than in NO?

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Aayush Kumari

Beginner-Level 5

The NO (Nitric Oxide) has 11 valence electrons while the NO? (Nitrosonium ion) has 10 valence electrons due to removal of one antibonding electron. Due to this, the bond order of NO increases from? 2.5 to 3 in the NO? (Nitrosonium ion).

As per the NCERT, since the bond order of NO? (3) is higher than that of NO (2.5), the bond in Nitrosonium ion is stronger bond and the stronger the bond, the shorter bond length.

Hence bond length in NO? is shorter the NO.

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Chemistry Class 12th

A compound 'X' is a weak acid and it exhibits colour change at pH close to the equivalence point during neutralization of NaOH with CH₃COOH. Compound 'X' exists in ionized form in basic medium. The compound 'X' is

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alok kumar singh

Contributor-Level 10

Phenolphthalein is the indicator of weak acid which produces pink colour in basic medium.

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a year ago

Chemistry Class 12th

For kinetic study of the reaction of iodide ion with H₂O₂ at room temperature:

(A) Always use freshly prepared starch solution.

(B) Always keep the concentration of sodium thiosulphate solution less than that of Kl solution.

(C) Record the time immediately after the appearance of blue colour.

(D) Record the time immediately before the appearance of blue colour.

(E) Always keep the concentration of sodium thiosulphate solution more than that of Kl solution.

Choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Always fresh solution of starch used and recorded immediately after the blue colour appears. Na2S2O3 is used in limited amount.

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a year ago

Chemistry Biomolecules

Given below are two statements : One is labeled as Assertion A and the other is labelled as Reason R

Assertion A : Amylose is insoluble in water.

Reason R: Amylose is a long linear molecules with more than 200 glucose units.

In the light of the above statements, choose the correct answer from the options given below

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alok kumar singh

Contributor-Level 10

Amylose is the water soluble compound.

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a year ago

Chemistry Class 12th

Statement about Enzyme Inhibitor Drugs are given below:

(A) There are Competitive and Non-competitive inhibitor drugs.

(B) These can bind at the active sites and allosteric sites.

(C) Competitive Drugs are allosteric site blocking drugs.

(D) Non-competitive Drugs are active site blocking drugs.

Choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Enzyme inhibitors are competitive inhibitors if they inhibit the attachment of substrate on active site of enzyme. Enzyme inhibitors are non- competitive inhibitors if they changes the active site of enzyme after binding at allosteric site.

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a year ago

Chemistry Biomolecules

For the below given cyclic hemiacetal (X), the correct pyranose structure is:

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Vishal Baghel

Contributor-Level 10

->Correct pyranose structure.

-> -OH group in left is up and –OH group in right is below.

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