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Chemistry Class 11th

Consider the species CH4, $N H_{4}^{+} a n d B H_{4}^{-} .$ $_{}^{}_{}^{}$ Choose the correct option with respect to the there species

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Vishal Baghel

Contributor-Level 10

Species =CH4 $_{}^{}$ $N H_{4}^{+}$ $B H_{4}^{?}$ $_{}^{}$

Electrons =101010

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Chemistry Class 11th

Which of the following is the correct plot for the probability density $ψ^{2} (r)$ $^{}$ as a function of distance 'r' of the electron from the nucleus for 2s orbital?

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Vishal Baghel

Contributor-Level 10

For 2S, number of radial moles = $n - l - 1 = 2 - 0 - 1 = 1$ and $^{}$ $Ψ^{2} (r)$ will always be positive

$∴ o p t i o n (B) i s c o r r e c t ?$ it has one radial node and it is positive.

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Chemistry Class 11th

Using the rules for significant figures, the correct answer for the expression $\frac{0.02858 * 0.112}{0.5702}$ $\frac{}{}$ will be

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Vishal Baghel

Contributor-Level 10

$\frac{0.02858 * 0.112}{0.5702} = 0.0561$

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8 months ago

Chemistry Chemistry Chemical Bonding and Molecular Structure

A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of $\frac{[C H_{3} C H_{2} C O O^{-}]}{[C H_{3} C H_{2} C O O H]}$ required to make buffer is_________.

Given : $K_{a} (C H_{3} C H_{2} C O O H) = 1.3 * 1 0^{- 5}$

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alok kumar singh

Contributor-Level 10

pH of acidic buffer is given by,

pH = pKa + log₁₀ $\frac{[S a l t]}{[a c i d]}$ $\frac{}{}$

or, $p = p k a + l o g_{10} \frac{[C H_{3} C H_{2} C O O^{-}]}{[C H_{3} C H_{2} C O O H]}$ $_{} \frac{_{}_{}^{}}{_{}_{}}$

or, $[H^{+}] = k_{a} \frac{[C H_{3} C H_{2} C O O H]}{[C H_{3} C H_{2} C O O^{-}]}$ $^{}_{} \frac{_{}_{}}{_{}_{}^{}}$

$\frac{[C H_{3} C H_{2} C O O^{-}]}{[C H_{3} C H_{2} C O O H]} = \frac{k_{a}}{[H^{+}]} = \frac{1.3 * 1 0^{- 5}}{1 0^{- 4}} = 0.13$

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8 months ago

Chemistry Class 11th

In the structure of SF₄, the lone pair of electrons on S is in.

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alok kumar singh

Contributor-Level 10

Geometry of SF₄ is trigonal bipyramidal, in which there is one lonepair which occupy equatorial position as,

There are two lone pair – bond pair repulsions at 90°

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Chemistry Structure of Atom

Consider the following statements:

(A) The principal quantum number 'n' is a positive integer with values of 'n' = 1, 2, 3,….

(B) The azimuthal quantum number $' l'$ for a given 'n' (principal quantum number) can have values as $' l' = 0, 1, 2, . . . n$

(C) Magnetic orbital quantum number $' m_{l}'$ for a particular $' l'$ (azimuthal quantum number) has $(2 l + 1)$ values.

(D) $\pm 1 / 2$ are two possible orientations of electron spin.

(E) For $l = 5,$ there will be a total of 9 orbitals

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alok kumar singh

Contributor-Level 10

$•$ Values of principal quantum number, n = 1, 2, 3, .

$•$ Values of azimuthal quantum number, $l = 0, 1, 2 . . . . . . . . . . ., n - 1$

$•$ Number of values of magnetic quantum number are $2 l + 1 .$

$•$ Values of spin quantum number are $\pm \frac{1}{2} .$

$•$ Number of orbitals for particular value of $l a r e 2 l + 1, s o f o r l = 5,$ no. of orbitals = 11.

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Chemistry Chemistry Some Basic Concepts of Chemistry

Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,

Given : Atomic masses of C,H and N are 12, 1 and 14 amu respectively. The molar mass of the compound A is 162 g mol^-1.

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alok kumar singh

Contributor-Level 10

Empirical formula is C₅H₇N

Empirical mass = 81

Molecular mass = 162

So, molecular formula is C₁₀H₁₄N₂

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Chemistry Class 12th

The number of oxygen's present in a nucleotide formed from a base, that is present only in RNA is_______________.

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Payal Gupta

Contributor-Level 10

Consider the following image

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Chemistry Class 12th

Compound 'P' on nitration with dil. HNO₃ yields two isomers (A) and (B). These isomers can be separated by steam distillation. Isomers (A) and (B) show the intramolecular and intermolecular hydrogen bonding respectively. Compound (P) on reaction with conc. HNO₃ yields a yellow compound 'C'___________

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Payal Gupta

Contributor-Level 10

Intermolecular H- bonding and intra-molecular H- bonding producing compound may be the phenol derivatives.

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Chemistry Class 12th

On complete combustion 0.30g of an organic compound gave 0.20g of carbon dioxide and 0.10 g of water. The percentage of carbon in the given organic compound is __________. (Nearest integer)

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Payal Gupta

Contributor-Level 10

Complete combustion of compound produces 0.2 gm CO₂

Hence wt of carbon in 0.2 gm CO₂

$= (\frac{12}{44} * 0.2) g m$

Therefore % of carbon in compound

$= \frac{w t o f c a r b o n * 100}{w t o f c o m p o u n d} = \frac{12 * 0.2 * 100}{44 * 0.3} = \frac{2400}{44 * 3} = 18.18 \approx 18 %$

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