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Chemistry Alcohols, Phenols and Ethers

The correct order of melting points of hydrides of group 16 elements is

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Payal Gupta

Contributor-Level 10

Due to H- bond in water, it has high melting point and melting point of other hydrides of the group are depending upon the molecular weight.

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a year ago

Chemistry Haloalkanes and Haloarenes

The correct order of melting point is

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Payal Gupta

Contributor-Level 10

Due to high crystallity Be has the highest M.P.

Be = 1560 K

Mg = 925 K

Ca = 1120 K

Sr = 1062 K

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a year ago

Chemistry Coordination Compounds

Consider the following reaction.

$2 H S O_{4}^{-} (a q) \to_{(2) H y d r o l y s i s}^{(1) E l e c t r o l y s i s} 2 H S O_{4}^{-} + 2 H^{+} + A$

The dihedral angle in product A in its solid phase at 110 K is

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Payal Gupta

Contributor-Level 10

During the electrolysis of dilute H₂SO₄

$2 H_{2} S O_{4} \overset{(1) e l e c t r o l y s i s}{\to} 2 H S O_{4}^{-} + 2 H^{+}$

$H_{2} S_{2} O_{8} + 2 H_{2} O \overset{h y d r o l y s i s}{\to} 2 H_{2} S O_{4} + \underset{(A)}{H_{2} O_{2}}$

$2 H^{+} + 2 e \to H_{2} ↑$

In the solid form of $H_{2} O_{2}$ dihedral angle is equal to 90.2°.

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Chemistry The d and f Block Elements

Given below are two statements:

Statement I: According to the Ellingham diagram, any metal oxide with higher is more stable that the one with lower .

Statement II: The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the oxide of a metal placed higher in the diagram.

In the light of the above statements, choose the most appropriate answer form the options given below

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Payal Gupta

Contributor-Level 10

According to Ellingham diagram, the metal oxide with lower $Δ G^{o}$ is more stable than metal oxide of higher $Δ G^{o}$ at same temperature.

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Chemistry General Principles and Isolation of Elements

The ${(\frac{\partial E}{\partial T})}_{P}$ of different types of half cells are as follows:

(Where E is the electromotive force )

Which of the above half cells would be preferred to be used as reference electrode

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Payal Gupta

Contributor-Level 10

$\frac{d E}{d T}$ is the temperature Co-efficient of cell. The cell having less variation of EMF, with respect to temperature have high efficiency.

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Chemistry Surface Chemistry

Consider the ions /molecule $O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$

For increasing bond order the correct option is

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Payal Gupta

Contributor-Level 10

$B o n d o r d e r = \frac{e^{-} o f B o n d i n g M O - e^{-} o f A B M O}{2}$

Hence Bond order for $O_{2}^{+} = \frac{10 - 5}{2} = 2.5$

$O_{2} = \frac{10 - 6}{2} = 2.0$

$O_{2}^{-} = \frac{10 - 7}{2} = 1.5$

$O_{2}^{- -} = \frac{10 - 8}{2} = 1.0$

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Chemistry Chemical Bonding and Molecular Structure

If the radius of the 3^rd Bohr's orbit of hydrogen atom r₃ and the radius of 4^th Bohr's orbit is r₄. Then

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Payal Gupta

Contributor-Level 10

Radius of Bohr's orbit $R_{n} = 0.529 \overset{o}{A} * \frac{n^{2}}{z}$

Radius of Bohr's orbit for hydrogen, $R_{n} = 0.529 \overset{o}{A} * n^{2}$

For third orbit (R₃) = $0.529 \overset{o}{A} * 9$ = r₃ and

Fourth orbit (R₄) = $0.59 \overset{o}{A} * 16 = r_{4}$

$∴ r_{4} = \frac{16 r_{3}}{9}$

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Chemistry Classification of Elements and Periodicity in Prop

An evacuated glass vessel weights 40.0g when empty, 135.0g when filled with a liquid of density 0.95 g mL^-¹ and 40.5 g when filled with an ideal gas at 0.82 atm at 250 K. The molar mass of the gas in g mo^-¹ is:

(Given: R = 0.082 L atm K^-¹ mol^-¹)

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Payal Gupta

Contributor-Level 10

Wt of liquid = 135 – 40 = 95 gm

Volume of liquid = $\frac{w t .}{d e n s i t y} = \frac{95}{0.95} = 100 m l$

Hence volume of vessel = 100 ml = 0.1 lit from ideal gas equation,

$M = \frac{d R T}{P} = \frac{0.5}{0.1} * \frac{0.0821 * 250}{0.82}$

$∴ M = 125 g / m o l$

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Chemistry Some Basic Concepts of Chemistry

A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is

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Payal Gupta

Contributor-Level 10

$M o l a l i t y = \frac{m o l e s o f s o l u t e * 1000}{w t o f s o l v e n t (g m)}$

$M o l a l i t y = \frac{35 * 1000 * 1.46}{36.5 * 100}$ = 14.0 M

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a year ago

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Eleven

Given below are two statements:

Statement I : Phenols are weakly acidic

Statement II : Therefore they are freely soluble in NaOH solution and are weaker acids than alcohols and water

Choose the most appropriate options:

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alok kumar singh

Contributor-Level 10

Phenol is weakly acidic compound but it is more acidic than alcohol and water because its conjugate base is more stable. Hence statement -I is correct while statement -II is wrong.

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