Chemistry

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New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

is optically active as it does not contain any element of symmetry.

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Correct order of increasing field strength of ligands is : I < OH< NCS

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9 months ago

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A
alok kumar singh

Contributor-Level 10

EAN = Atomic No. – Oxidation state + 2 * CN

= 26 – 2 + 2 * 6

=36

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

HBrO2 has least existence

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9 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

NO is a neutral oxide.

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9 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Higher the value of (ixM), higher will be the boiling point of solution.

Solute

Glucose

NaCl

K2SO4

K4 [Fe (N)6]

van't Hoff

factor (i)

1

2

3

5

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