Chemistry

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The average bond enthalpy is defined as the ratio of total bond dissociation enthalpy to the number of bonds broken in the structure.

The identical O- H bonds in water molecule does not have the same bond enthalpies. According to the structure of a water molecule, there are two O- H bonds, but there is a change in the breaking of the first O- H bond than the second because of the different charge.

Hence in water molecule the average bond enthalpy will be:

The average O-H bond enthalpy = 502 + 427 2 = 464 mol-1

In ethanol C2H5OH  the bond enthalpy of O-H is different becaus

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a year ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: All the C-Obonds in carbonate ion (CO32-) are equal in length due to the equivalent resonance of all the three carbon-oxygen bonds gets a double bond character atleast once. This type of double bond character happened throughout 3C- O skeleton, and hence all the bonds acquired equal bond length.

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: In compound BCl3, Boron has sp2-hybridisation and the shape is Triangular Planar.

In methane CH4, Carbon has sp3 -hybridization and shape are Tetrahedral.

In carbon dioxide CO2, carbon has sp-hybridisation and shape is Linear.

In ammonia NH3, nitrogen has sp3-hybridisation and shape is Pyramidal.

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: (i)

 

(ii)

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: (i) According to the electronic configuration, a total of 8 electrons must be present in the valence shell of an element. Element X has 4 valence electrons, so it will share the remaining 4 electrons for the formation of the bond, the molecular formula will be XH4 . The element Y has 5 valence shell electrons, so it will form 3 bonds and the formula will be YH3 . The element Z has 7 valence shell electrons, so it will form one bond with hydrogen and has the molecular formula H-Z .

(ii) Elements X, Y and Z having, 5 and 4 7 valence electrons respectively belongs

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: BeCl2 has a linear structure

HOCl is also non-linear in structure.

H2O has a V-shaped structure.

Cl2O has a V-shaped structure.

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a year ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The hybridization of Carbon 1 is sp, carbon 2 is sp, carbon 3 sp2, carbon 4 is sp3 and carbon 5 is sp2. The triple bond has 2 pie bonds and one sigma bond. Each double bond has one sigma and one pie bond. Every single bond is a sigma bond. Thus, the total number of sigma bonds is 11 and pie bonds are 4.

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a year ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The carbonate ion CO32- can be best represented by its resonating structures. The carbonate ion cannot be represented by a single Lewis structure because the three carbon oxygen bond lengths are the same. This cannot be shown by a single Lewis structure. For showing the similar lengths of all the carbon to oxygen bonds three hybrid structures are constructed which are in resonance with each other.

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

N—H, F—H, C—H and O—H

Ans: The ionic character in a molecular species is decided by the electronegativity difference between the two bonded atoms. Greater the electronegativity difference between two bonded pairs, the greater will be the ionic character. The electronegativity difference of the given species is

C - F = (2.5 - 2.1) = 0.4

N -H = (3.0 - 2.1) = 0.9

O - H = (3.5 - 2.1) = 1.4

F - H = (4.0 - 2.1) = 1.9

According to the above given difference in the electronegativities, the order of increasing ionic character is:

C – H< N - H

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Ionic bonds are such bonds in which complete transfer of electrons from one atom to another atom. Due to complete transfer positive and negative ions are formed in this bond. The ions in this bond are held together by electrostatic force of attraction. The formation of calcium fluoride CaF2 leads to the formation of an ionic bond.

Ca→  Ca2+ + e -   The electronic configuration of  Ca= [Ar] 4s2   and Ca2+= [Ar]

F +e -→F- The electronic configuration of F= [He] 2p5  and F = [He ]2p6

Thus Ca2+ +2F- → CaF2

A covalent bond is forme

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