Chemistry

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Payal Gupta

Contributor-Level 10

3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct

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alok kumar singh

Contributor-Level 10

1.43 There is one octahedral hole for each atom in hexagonal close packed arrangement. If the number of oxide ions (O2−) per unit cell is 1, then the number of

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Vishal Baghel

Contributor-Level 10

Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.

Step 2. Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene 'A' is

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alok kumar singh

Contributor-Level 10

1.42 The ratio less than 2:1 in Cu2O shows that some cuprous (Cu+) ions have been replaced by cupric (Cu+2) ions. To maintain electrical neutrality, every two Cu+ ions will be replaced by one Cu+2 ion, thereby creating a hole. As conduction will be due to the presence of these positive holes, hence it is a p -type semi conductor

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Payal Gupta

Contributor-Level 10

3.37.  (d) is incorrect.

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Vishal Baghel

Contributor-Level 10

(a) Isomers of C4H8 having one double bond are:

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alok kumar singh

Contributor-Level 10

1.41 These solids have conductive in the intermediate range from 10−6 to 104ohm−1m−1. As there is rise in 
the temperature, conductivity also increases because electrons from the valence band jump to 
conduction band.
Types of semiconductors
(a) n - type semiconductor when silicon or germanium crystal is doped with group 15 element like P or 
As, the dopant atom forms four covalent bonds like a Si or Ge atom but the fifth electron no used in 
bonding, becomes delocalised and contribute its share towards electrical conduction. Thus, silicon or 
germanium doped with P or As is called n-type semiconductor (negative

...more

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Vishal Baghel

Contributor-Level 10

(a) 2-Methykbuut-2-ene

(b) Pent-1-ene-3-yne

(c) But-1,3-diene

(d) 4-Phenylbut-1-ene

(e) 2-Methyl phenol (f) 5- (2-Methylpropyl)decane

(g) 4-Ethyldeca-1,5,8-triene

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Vishal Baghel

Contributor-Level 10

Chlorination of methane is a free radical reaction which occurs by the following mechanism involving initiation, propagation and termination steps:

From the above mechanism, it is evident that during the propagation step, CH3 free radicals are produced, which may undergo three reactions, i.e., (i), (ii) and (iii). In the chain termination step, the two CH3 free radicals combine to form ethane (CH3—CH3) molecule.

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