Chemistry
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a year agoContributor-Level 10
3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct
New answer posted
a year agoContributor-Level 10
1.43 There is one octahedral hole for each atom in hexagonal close packed arrangement. If the number of oxide ions (O2−) per unit cell is 1, then the number of

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a year agoContributor-Level 10
Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.


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a year agoNew answer posted
a year agoContributor-Level 10
1.42 The ratio less than 2:1 in Cu2O shows that some cuprous (Cu+) ions have been replaced by cupric (Cu+2) ions. To maintain electrical neutrality, every two Cu+ ions will be replaced by one Cu+2 ion, thereby creating a hole. As conduction will be due to the presence of these positive holes, hence it is a p -type semi conductor
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a year agoContributor-Level 10
1.41 These solids have conductive in the intermediate range from 10−6 to 104ohm−1m−1. As there is rise in
the temperature, conductivity also increases because electrons from the valence band jump to
conduction band.
Types of semiconductors
(a) n - type semiconductor when silicon or germanium crystal is doped with group 15 element like P or
As, the dopant atom forms four covalent bonds like a Si or Ge atom but the fifth electron no used in
bonding, becomes delocalised and contribute its share towards electrical conduction. Thus, silicon or
germanium doped with P or As is called n-type semiconductor (negative
New answer posted
a year agoContributor-Level 10
(a) 2-Methykbuut-2-ene
(b) Pent-1-ene-3-yne
(c) But-1,3-diene
(d) 4-Phenylbut-1-ene
(e) 2-Methyl phenol (f) 5- (2-Methylpropyl)decane
(g) 4-Ethyldeca-1,5,8-triene
New answer posted
a year agoContributor-Level 10
Chlorination of methane is a free radical reaction which occurs by the following mechanism involving initiation, propagation and termination steps:

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