Class 11th

pH = pK? + log ( [CH? COONa] / [CH? COOH])
pH = 4.57 + log (0.1 / 0.01) = 5.57

MgH? is an ionic or saline hydride, GeH? is an electron precise hydride with 8 electrons around Ge, B? H? is an electron deficient hydride and HF is electron rich.

In diborane the boron atoms are sp³ hybridized.

Displacement equation of SHM of frequency ' $n$  '

$\mathrm{x}=\mathrm{A}\mathrm{s}\mathrm{i}\mathrm{n}?\left(\omega \mathrm{t}\right)=\mathrm{A}\mathrm{s}\mathrm{i}\mathrm{n}?\left(2\pi \mathrm{n}\mathrm{t}\right)$

Now,

Potential energy $U=\frac{1}{2}{\mathrm{k}\mathrm{x}}^2=\frac{1}{2}{\mathrm{K}\mathrm{A}}^2{\mathrm{s}\mathrm{i}\mathrm{n}}^2?2\pi \mathrm{n}\mathrm{t}$

$=\frac{1}{2}{\mathrm{k}\mathrm{A}}^2\left. [\frac{1-\mathrm{c}\mathrm{o}\mathrm{s}?2\pi 2\mathrm{n}\mathrm{t}}{2}\right]$

So frequency of potential energy $=2n$

Molality = moles of solute / mass of solvent (kgs) ⇒ 1 = 0.5 / W (kgs)
W_solvent (kgs) = 0.5 = 500 g

The boiling point order is: H? S < H? Se < H? Te < H? O

The concept of delocalization or resonance can be explained for quantum mechanical atomic models in which electrons are considered to be spread over the entire molecular orbital.

The fundamental assumption of the valence bond theory contradicts the delocalization. The valence bond theory assumes that a covalent bond forms from the overlap of atomic orbitals on adjacent atoms, and electron density is localized between two specific nuclei.

That is why VBT cannot explain energy stabilization due to the resonance property.

Plane angle and solid angle are dimensionless but have units.

$\begin{array}{rr}& \mathrm{v}\propto \sqrt[]{\mathrm{T}}\\ & \frac{{\mathrm{v}}_{\mathrm{i}}}{{\mathrm{v}}_{\mathrm{f}}}=\sqrt[]{\frac{1}{2}}=\frac{1}{\sqrt[]{2}}\end{array}$