Class 11th

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New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

For first resonance,

l + 0 . 3 d = v 4 f

⇒ l + 0 . 3 * 6 = 3 3 6 * 1 0 0 4 * 5 0 4 ⇒ l = 1 4 . 8 c m

New answer posted

a year ago

0 Follower 75 Views

A
alok kumar singh

Contributor-Level 10

For 3S number of radial nodes are

= n − l − 1 = 3 − 0 − 1 = 2

          

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π l g

⇒ 2 = 2 π 2 g

⇒ g = 2 π 2 m / s 2

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Ca (OH)2 ?  Ca+ + 2OH-

S                      S           2S

∴ K s p = 4 S 3

            

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

At constant pressure,

d U = n C V d T = n . 5 2 R     d T

d Q = n C P d T = n . 7 2 R     d T

dW = nRdT

dU : dQ : dW = 5 : 7 : 2

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

SF4 has sp3d hybridization and one type is axial while other type is equatorial

SiF4 has sp3 (all bonds are equal)

B F 4 − has sp3 (all bonds are equal)

XeF4 has sp3d2 and shape is sq. planar (All bonds are equal)

New answer posted

a year ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Thermal stress is developed on heating when expansion of rod is hindered.

New answer posted

a year ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

L C = 1 1 0 0 m m = 0 . 0 1 m m

Zero error = +0.08 mm.

Diameter = 1 + 72 * 0.01 – 0.08 = 1.64 mm

Radius = 0.82 mm

New answer posted

a year ago

0 Follower 20 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

( v e ) A = ( v e ) B ⇒ M 1 R 1 = M 2 R 2

R is not correct.

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