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P
Payal Gupta

Contributor-Level 10

5.34. The temperature at which the vapour pressure of a liquid is equal to external pressure is called boiling point of liquid.

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Payal Gupta

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5.33. Molecules of liquids are held together byattractive intermolecular forces. Liquids havedefinite volume because molecules do notseparate from each other. However, moleculesof liquids can move past one another freely, therefore, liquids can flow, can be poured andcan assume the shape of the container in whichthese are stored.

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Vishal Baghel

Contributor-Level 10

(a) Phosphorous, chlorine and sulphur are the non metals which can show disproportionation reaction. The reactions shown are:

P4? + 3OH? + 3H2? O? PH3? + 3H2? PO2?

? Cl2? + 2OH? ? Cl? + ClO? + H2? O

S8? +12OH? ?4S2? +2S2? O32? ? +6H2? O

 

(b) Copper, gallium and indium are the metals that show disproportionation reaction. 

The reactions are shown below.

2Cu+? Cu2+ + Cu

3Ga+? Ga3+ + 2Ga

3In+? In3+ + 2In

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Payal Gupta

Contributor-Level 10

5.32.  (c) F2

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Payal Gupta

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5.31.  (b) frictional resistance

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Payal Gupta

Contributor-Level 10

5.30.  (a) decreases

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Vishal Baghel

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The balanced chemical reaction for the redox reaction between chlorine and sulphur dioxide is:

Cl2? + SO2? + 2H2? O → 2Cl + SO42− ? + 4H+.

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Vishal Baghel

Contributor-Level 10

(a) F. Fluorine being the most electronegative element shows only a -ve oxidation state of -1.

(b) Cs. Alkali metals because of the presence of a single electron in the valence shell, exhibit an oxidation state of +1.

(c) I. Because of the presence of seven electrons in the valence shell, I shows an oxidation state of -1 (in compounds of I with more electropositive elements such as H, Na, K, Ca, etc.) or an oxidation state of +1 compounds of I with more electronegative elements, i.e., O, F, etc.) and because of the presence of d-orbitals it also exhibits +ve oxidation states of +3, +5 and +7.

(d) Ne. It is an inert gas (with high ioni

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Payal Gupta

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5.29.  (b) increases by three times

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Vishal Baghel

Contributor-Level 10

The unbalanced chemical reaction is:
Mn3+ (aq) → Mn2+ (aq) + MnO2? (s) + H+ (aq)
The oxidation half reaction is,  
Mn3+ (aq) → MnO2? (s).
To balance oxidation number, one electron is added on R.H.S.
Mn3+ (aq) → MnO2? (s) + e
4 protons are added to balance the charge.
Mn3+ (aq) → MnO2? (s) + 4H+ (aq) + e
2 water molecules are added to balance O atoms.
The reduction half reaction is Mn3+ (aq) → Mn2+ (aq).
An electron is added to balance oxidation number.
Mn3+ (aq) + e → Mn2+ (aq)
Two half-cell reactions are added to obtain balanced chemical equation.
2Mn3+ (aq) + 2H2? O (l) → Mn2+ (aq) + MnO2? (s) + 4H+ (aq)

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