Class 11th
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8 months agoContributor-Level 10
(a) Here, HO– acts as a nucleophile as it is an electron-rich species, i.e., it is a nucleus-seeking species.
(b) Here, –CN acts as a nucleophile as it is an electron-rich species, i.e., it is a nucleus-seeking species.
(c) CH3C+O acts as an electrophile as it is an electron deficient species.
New answer posted
8 months agoContributor-Level 10
Electrophiles: The name electrophiles mean electron loving. Electrophiles are electron deficient. They may be positive ions or neutral molecules.
Ex: H+, Cl+, Br+, NO2+, R3C+, RN2+, AlCl3, BF3
Nucleophiles: The name nucleophiles means 'nucleus loving' and indicates that it attacks the region of low electron density (positive centres) in a substrate molecule. They are electron rich they may be negative ions or neutral molecules.
Ex: Cl– Br–, CN–, OH–, RCR2–, NH3, RNH2, H2O, ROH etc.
New answer posted
8 months agoContributor-Level 10
Due to hyperconjugation, alkyl groups act as electron donors when attached to a π - system as shown below:

New question posted
8 months agoNew answer posted
8 months agoContributor-Level 10
Nitroethoxide ion (O2NCH2CH2O–) is more stable than ethoxide ion (CH3CH2O–) due to -I effect of nitro group which decreases the negative charge of oxide ion of nitroethoxide ion leading to stability. In contrast, CH3CH2 has +I-effect. It, therefore, tends to intensify the -ve charge and hence destabilizes it.
New answer posted
8 months agoContributor-Level 10
4.29 (c) It will not form a sigma bond because taking x-axis as the inter-nuclear axis, there will be lateral overlap between the two 2py orbitals forming a -bond.
New question posted
8 months agoNew answer posted
8 months agoContributor-Level 10
4.28. (a) Acetylene C2? H2? contains 3? bonds and 2? bonds.
(b) Ethylene C2? H4? contains 5? bonds and 1? bond.

New answer posted
8 months agoContributor-Level 10
(a) H-COOH
CH3—COOH
CH3CH2—COOH
CH3CH2CH2—COOH
CH3CH2CH2CH2—COOH
(b) CH3COCH3
CH3COCH2CH3
CH3COCH2CH2CH3
CH3COCH2CH2CH2CH3
CH3CO (CH3)4CH3
(c) H—CH=CH2
CH3CH=CH2
CH3CH2CH=CH2
CH3CH2CH2CH=CH2
CH3CH2CH2CH2CH=CH2
New answer posted
8 months agoContributor-Level 10
(a) 2, 2-Demethylpentane
(b) 2, 4, 7-Trimethyloctane. For two alkyl groups on the same carbon its locant is repeated twice, 2, 4, 7-locant set is lower than 2, 5, 7.
(c) 2- Chloro-4-methylpentane. Alphabetical order of substituents, (d) But-3-yn-1-ol. Lower locant for the principal functional group, i.e., alcohol.
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