Class 12th

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New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

By conservation of energy
(K.E. + P.E.)? = (K.E. + P.E.)?
0 + (1/ (4πε? a³) * 2P * P = 2 * (1/2)mv² + 0
v = √ (p² / (2πε? ma³) = (P/a) * √ (1 / (2πε? ma)

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Sol. eVslop = hc/λ - φ

Slope of curve

tan θ = hc/e = constant
as intensity of incident radiation is increased, there will be no effect on graph

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Q? = CV?
U? = ½CV? ²
q? = (q? C)/ (C + C/2) = 2q? /3

q? = (q? (C/2)/ (C + C/2) = q? /3; Uf = q? ²/2C + q? ²/2 (C/2)
= (4q? ²/9x2C) + (q? ²/9C)
= (6q? ²/18C) = q? ²/3C = CV? ²/3

Energy loss in the process = U? – Uf
= ½CV? ² - CV? ²/3
= CV? ²/6

New answer posted

2 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

2 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Cr²? and Fe²? both have 4 unpaired electrons.

New answer posted

2 months ago

0 Follower 11 Views

S
Syed Aquib Ur Rahman

Contributor-Level 10

In Rutherford's model, electrostatic force provides the centripetal force:

1 4 πE    

Kinetic Energy (K):

K = 1 2 m v 2 = e 2 8 π E 0 r

Potential Energy (U):

U = 1 4 π E 0 e 2 r  

Total Energy (E):

E = K + U = e 2 8 π E 0 r

 

Note that, E is the Epsilon symbol. 

New answer posted

2 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Since, lim (x→0) f (x)/x exist ⇒ f (0) = 0
Now, f' (x) = lim (h→0) (f (x+h)-f (x)/h = lim (h→0) (f (h)+xh²+x²h)/h (take y = h)
= lim (h→0) f (h)/h + lim (h→0) (xh) + x²
⇒ f' (x) = 1 + 0 + x²
⇒ f' (3) = 10

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

D = |1 -2 3; 2 1; 1 -7 a| = 0 ⇒ a = 8
also, D? = |9 -2 3; b 1; 24 -7 8| = 0 ⇒ b = 3
hence, a-b = 8-3=5

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