Class 12th

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New answer posted

5 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

From the given options only option (c) is correct.

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

From the above 2 cases, it follows case (I) and number of persons sitting between P2 and P4 is either 1 or 3.

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

From the above 2 cases.

In case (I) if P12 is sitting opposite to P8 then P6 is sitting opposite to P7. In case (II) if P12 is sitting opposite to P8 then P10 is sitting opposite to P7.

New answer posted

5 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Input are :

(0, 0) ; (0, 1); (1, 0); (1, 1).

Thus, the output y is : (1, 0) s

A

B

P

Q

Y

0

0

0

0

1

0

1

0

1

1

1

0

0

1

1

1

1

1

1

0

New answer posted

5 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

From the given information we can conclude that (P3) and (P4) are at seat numbers 7 and 6, respectively. And (P11) is the only person between (P3) and (P10) while (P1) is opposite to (P11). Hence, (P1), (P11) and (P10) must be at seat numbers 5, 8 and 9 respectively.

Then we have following two cases:

From the above 2 cases, it follows case (I) and opposite to P6 is either P12 or P2.

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

Please find the answer below

New answer posted

5 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Please find the answer below

New answer posted

5 months ago

Directions for questions: Read the information carefully and answer the questions given below.

There were ten events in the last years “annual cultural festival” of xyz international College. Following guidelines have been issued to schedule the “annual cultural festival”:

I. A college board has organized the ten events Z1, Z2, Z3, Z4, Z5, Z6, Z7, Z8, Z9, Z10 on six days of week with holiday on Sunday; not having more than two events on any of the days.

II. Event begins on Wednesday with event Z6.

III. Z4 is accompanied by some other event but not on Thursday. Z1 and Z7 are on the same day immediately after the holiday.

IV

...more
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P
Payal Gupta

Contributor-Level 10

According to the information provided following arrangement of the schedule will be formed.

Wed

Thu

Fri

Sat

Sun

Mon

Tue

Z6, Z2

Z8, Z5

Z9, Z4

Z3

*

Z1, Z7

Z10

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Since, Kathak has one more dancer than Bhangra, there are 4 dancer in Kathak S4, S5, S6 and S9. Remaining dancers are in Bharatnatyam. So, option (a) is correct

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

If the Bharatnatyam team has just one member S10, then the Kathak team will surely have S4, S5 and S6 as dancers.

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