Class 12th

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New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

Please find the answer below

New answer posted

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Please find the answer below

New answer posted

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Room

Person

R1

-

R2

-

R3

-

R4

-

R5

-

R6

-

 

P2, P5 and P8 are women

From (III) and the other given facts, two women will live in room R3. From (III) and (VI), P1 will live in room R5.

From (VII) & (III) P5 will be in R3 and P6 will be R6 Hence P2 and P5 will live in room R3. Now the whole scene looks like this:

 

Room

Perso

 

 

n

R1

P4, P3

R2

P8/P7

R3

P2, P5

R4

P8/P7

R5

P1

R6

P6

New answer posted

11 months ago

0 Follower 19 Views

A
alok kumar singh

Contributor-Level 10

f(x) = tan-1 (sin x + cos x)

a s x [ 0 , π 2 ]              so  1 s i n x + c o s x 2  

so f ( x ) [ t a n 1 1 , t a n 1 2 ]  

->M = tan-1   2 & m = t a n 1 1 = π 4

Now, tan (M – m) = tan ( t a n 1 2 π 4 )

= 2 1 1 + 2 . 1 = 2 1 2 + 1 * 2 1 2 1 = 3 2 2  

             

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

( p q ) ( ( r q ) p )

( p q ) ( ( r q ) p )

[ ( p q ) ( r p ) ]

( p q ) ( r p )

( p q ) ( r p )

New answer posted

11 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

 0.02i * RG = 0.98i * 5

[in parallel, pot. Diff is same]

or, RG = 49 * 5

RG = 245 Ω

New answer posted

11 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Proton                electron

Charge :              +e                        -e

Wavelength :             λ                 λ

KE :                      KP          &

...more

New answer posted

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Molality (m) = ( 4 0 / 1 8 0 ) 0 . 2 = ( 1 0 9 ) m o l a l

Δ T f = T f T f ' = 1 . 8 6 * 1 0 9 K

T f ' = 2 7 3 . 1 5 1 . 8 6 * 1 0 9 K

= 2 7 1 . 0 8 K 2 7 1 K

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Energy of emitted photon in 0.1 sec = 10-4 J

n * h c λ = 1 0 4

n * 6 . 6 3 * 1 0 3 4 * 3 * 1 0 8 1 0 0 0 * 1 0 9 = 1 0 4

n = 5 . 0 2 * 1 0 1 4 = 5 0 . 2 * 1 0 1 3 5 0 * 1 0 1 3

 

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

κ = 1 R * l A = [ ( 1 1 5 0 0 ) * 1 . 1 4 ] S c m 1 = 1 . 1 4 1 5 0 0 S c m 1

λ m = κ M * 1 0 0 0 S c m 2 m o l 1

λ m = 1 0 0 0 * ( 1 . 1 4 1 5 0 0 ) 0 . 0 0 1 S c m 2 m o l 1 = 7 6 0 S c m 2 m o l 1

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