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New answer posted

12 months ago

0 Follower 27 Views

P
Payal Gupta

Contributor-Level 10

At constant Temp

P α 1 v

v2 > v1

⇒ P1 > P2

New answer posted

12 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

Amount of work done to bring mass from infinity to point (1) u1 = 0

Similarly, to bring mass (2) u 2 = G m d m

u 3 = G m d [ m 1 + m 2 ]

u 4 = G m d [ 2 m + m 2 ]

u 5 = G m d [ 4 2 M ]

U T = u 1 + u 2 + u 3 + u 4 + u 5

U T = G m d [ ( 4 + 2 ) m + 4 2 M ]

             
     

New answer posted

12 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Conservation of Energy b/w (1) & (2)

1 2 m v 2 + m g l = 1 2 m u 2

v = u 2 2 g l

Δ v = v j ^ u i ^

| Δ v | = ( u ) 2 + ( u 2 2 g l ) 2

= u 2 + u 2 2 g l

= 2 ( u 2 g l )

x = 2

New answer posted

12 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

F.B.D, with respect to Non-Inertial frame

k x = m ω 2 ( l 0 + x )

x | k m ω 2 ( l 0 + x )

x = m ω 2 l 0 k m ω 2

        

               

New answer posted

12 months ago

0 Follower 16 Views

P
Payal Gupta

Contributor-Level 10

Total time (T) = 4 sec

Given u = 0 m/sec

a = g = 9.8 m/sec2

h = 4.9 m, t =?

h = u t + 1 2 a t 2                

4 . 9 = 0 . t + 1 2 * 9 . 8 t 2                

t = 1 sec

'v' be the velocity with which ball hits the water v = u + at

= 0 + 9.8 * 1 = 9.8 m/sec

Time taken to reach the bottom of the lake from surface of the lake

= 4 – 1 = 3 sec

v = 9.8 m/sec

H = u t + 1 2 g t 2 = 9 . 8 * 3 + 1 2 * 9 . 8 * 9                

29.4 + 4.9 * 9 = 29.4 + 44.1

H = 73.5 m

New answer posted

12 months ago

0 Follower 21 Views

P
Payal Gupta

Contributor-Level 10

1° →  60'

⇒ 60' → 10°

6 0 ' π 1 8 0 C

θ = π * 2 * 1 0 3 1 8 0 * 3 6 0 0          

L = 1.5 * 1011 m

D = L θ = 1 . 5 * 1 0 1 1 * π 1 8 0 * 3 6 0 0 * 2 * 1 0 3 = 1 . 4 5 * 1 0 9 m    

   

New question posted

12 months ago

0 Follower 2 Views

New question posted

12 months ago

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New answer posted

12 months ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

S. I. unit Pascal – second   = N m 2 s e c  

= M L T 2 T L 2  

= M L 1 T 1  

New answer posted

12 months ago

0 Follower 2 Views

N
Nitesh Gulati

Contributor-Level 10

Candidates seeking admission to the PGDM programme can enroll for admission with Class 12 and graduation marks. Candidates must complete graduation to enroll for certificate course. Uma Krishna Shetty Institute of Management Studies and Research admits students based on entrance exam scores. To get admission to UKS Institute of Management, candidates must meet the eligibility criteria set by the college. The application process at UKS Institute of Management is conducted online.

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