Equilibrium

Get insights from 242 questions on Equilibrium, answered by students, alumni, and experts. You may also ask and answer any question you like about Equilibrium

Follow Ask Question
242

Questions

0

Discussions

6

Active Users

0

Followers

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (iv) 

Since in all the given reaction, the volume is to be kept constant and an inert gas argon is added which will do not take part in reaction. So, the equilibrium will remain unaffected in all the given cases.

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (i) 

If the equation is multiplied by 2, the equilibrium constant for the new equation is the square of K it means we must do the square of 5 that is 25. Then and on reversing the reaction the value of the equilibrium constant is inversed means the value of K comes out to be 1/25= 0.04. 

New answer posted

3 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (ii)

 Greater the boiling point, lower will be the vapour pressure.

New answer posted

3 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option(i)

The given reaction is :-

N2 (g) + 3H2 (g) ?2NH3 (g)

A/C to vart Hoff's eqn,

d l n K d T = ? M R T 2

K is dependent on temperature. As temperature remains constant at equilibrium, so K will remain constant in the given conditions.

New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option(i)

When the reaction is half completed, [A] = [B].
Thus, [B][A]=1
?G0=−RTInK=−RTIn(1)=0

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option(iii)

The equation for weak acid and weak base is given as-

pH=7+ 1 2  ?(pKa?−pKb?)

Ka=1.8*10-5

pKa=−log (1.8*10-5) =5−log1.8 =4.744

pKb?=−log (1.8*10-5) =4.744

pH=7+ 1 2  ?(pKa?−pKb?) =7

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (i)

pH for weak acid is given by the following equation:

pH= 1 2 [pKa−logC]

= 1 2 [−log (1.74*10−5)−log0.01]

=3.4

New answer posted

3 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (iv)

Aqueous ammonia will absorb chloride ions and thus the equilibria will shift in forward direction and solubility of silver chloride will increase.

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (iii)

When 0.1 mol dm-3 NH4OH and 0.05 mol dm-3 HCl react total amount of HCl reacts with NH4OH to form NH4Cl and some NH4OH will be left unreacted. Thus, the resultant solution contains NH4Cl and NH4OH which will produce a buffer solution.

New answer posted

3 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (iii)

 BF3 is an electron deficient species that is why it is a Lewis acid. (all Lewis acid can accept a pair of electrons.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.