Equilibrium

Get insights from 242 questions on Equilibrium, answered by students, alumni, and experts. You may also ask and answer any question you like about Equilibrium

Follow Ask Question
242

Questions

0

Discussions

6

Active Users

0

Followers

New answer posted

3 weeks ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

A ( g ) ? 2 B ( g ) .

E m 2 m o l V l 4 m o l V l

N e w E q m 4 x V 4 + 2 x V

V * 2 4 x 2 V 4 2 x 2 V

New Eqm 4 x y 2 V 4 + 2 x + 2 y 2 V

= 4 Z 2 V = 4 + 2 Z 2 V ( Z = x + y )

Now, KC =  [ B ] 2 [ A ] = constant

o r , ( 4 V ) 2 ( 2 V ) = ( 4 + 2 Z 2 V ) ( 4 Z 2 V ) Z = 1 . 2 9

 mole of B at new Eqm = 4 + 2Z = 6.58

New answer posted

4 weeks ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

From ΔG° = ΔH° – TΔS°

⇒ – 2.303RTlog Kc = ΔH° – TΔS° = 77.2 * 10³ – 400 * 122 = 28400 J

So log K? = (28400 / (2.303*8.314*400) ∴ [Kc = 1.958 * 10? ]

New answer posted

4 weeks ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

From Reaction

Δn? = 2 – 1 = 1

Kp = Kc (RT)^Δn?

Kp = Kc (RT)¹

Kc = Kp (RT)? ¹

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

All have same molarity, pH ∝ 1/ (Acidic strength) ∝ Basic strength

H? SO? → Acidic

NH? Cl (Salt of weak base and strong acid)

Acidic but less than H? SO?

NaCl → (Neutral solution)

NaOH → Basic (Strong Base)

So NaOH > NaCl > NH? Cl > H? SO?

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

and basic strength ∝ 1/pK? ∝ K? ∝ +R ∝ 1/ (-R) ∝ +I ∝ 1/ (-I)

So basic strength order ⇒ IV > III > II > I, so pK? order is IV < III < II < I

New answer posted

4 weeks ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

C l 2 ( g ) ? 2 C l ( g )                          

Initially ->             1 mol                   -

At eq.                      1-x mol               2x mol

Here; molecules of Cl2 = atoms of Cl

i.e moles of Cl2 = moles of Cl

So : 1 – x = 2x        x = 1/3

Moles of Cl2 at equ

...more

New answer posted

4 weeks ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kp = (Po? )¹/² = 4
Po? = 16 atm

New answer posted

4 weeks ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

BCl → B? + Cl?
B? + H? O? BOH + H? , K? = K? /K?
0.25 – –
(0.25 – x) x
Given, pH = 2.7 = [H? ] = 2 * 10? ³
∴ x²/ (0.25) = (10? ¹? )/K?
= 4 * 10? * 4 * K? = 10? ¹?
= K? = (1/16) * 10? = 6.25 * 10? ¹?

New answer posted

a month ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

When nucleoside is linked to phosphoric acid at 5 '-position of sugar moiety, we get nucleotide.

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

| List-I | | List-II |
| :- | :- | :- |
| (a) 2SO? (g) + O? (g) → 2SO? (g) | (iv) | Tropospheric pollution |
| (b) HOCl (g) - (hν)->? H +? l | (iii) | Ozone depletion |
| (c) CaCO? + H? SO? → | (i) CaSO? + H? O + CO? | Acid rain |
| (d) NO? (g) - (hν)-> NO (g) + O (g) | (ii) | Smog |

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.