Equilibrium

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New answer posted•a year ago
S
a year ago

A ( g ) ? 2 B ( g ) .

E m 2 m o l V l 4 m o l V l

N e w       E q m         4 − x V 4 + 2 x V

V × 2 4 − x 2 V   4 − 2 x 2 V

New Eqm 4 − x − y 2 V 4 + 2 x + 2 y 2 V

= 4 − Z 2 V = 4 + 2 Z 2 V ( Z = x + y )

Now, KC =  [ B ] 2 [ A ] = constant

o r , ( 4 V ) 2 ( 2 V ) = ( 4 + 2 Z 2 V ) ( 4 − Z 2 V ) ⇒ Z = 1 . 2 9

 mole of B at new Eqm = 4 + 2Z = 6.58

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New answer posted•a year ago
S
a year ago

From Reaction

Δn? = 2 – 1 = 1

Kp = Kc (RT)^Δn?

Kp = Kc (RT)¹

Kc = Kp (RT)? ¹

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New answer posted•a year ago
S
a year ago

All have same molarity, pH ∝ 1/ (Acidic strength) ∝ Basic strength

H? SO? → Acidic

NH? Cl (Salt of weak base and strong acid)

Acidic but less than H? SO?

NaCl → (Neutral solution)

NaOH → Basic (Strong Base)

So NaOH > NaCl > NH? Cl > H? SO?

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New answer posted•a year ago
S
a year ago

and basic strength ∝ 1/pK? ∝ K? ∝ +R ∝ 1/ (-R) ∝ +I ∝ 1/ (-I)

So basic strength order ⇒ IV > III > II > I, so pK? order is IV < III < II < I

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

BCl → B? + Cl?
B? + H? O? BOH + H? , K? = K? /K?
0.25 – –
(0.25 – x) x
Given, pH = 2.7 = [H? ] = 2 × 10? ³
∴ x²/ (0.25) = (10? ¹? )/K?
= 4 × 10? × 4 × K? = 10? ¹?
= K? = (1/16) × 10? = 6.25 × 10? ¹?

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

| List-I | | List-II |
| :- | :- | :- |
| (a) 2SO? (g) + O? (g) → 2SO? (g) | (iv) | Tropospheric pollution |
| (b) HOCl (g) - (hν)->? H +? l | (iii) | Ozone depletion |
| (c) CaCO? + H? SO? → | (i) CaSO? + H? O + CO? | Acid rain |
| (d) NO? (g) - (hν)-> NO (g) + O (g) | (ii) | Smog |

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New answer posted•a year ago