Equilibrium

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Given below are two statements : one is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Phenolphthalein is pH dependent indicator, remains colourless in acidic solution and gives pink colour in basic medium.

Reason R: Phenolphthalein is a weak acid. It doesn’t dissociate in basic medium.

**In the light of the above statements, choose the most appropriate answer from the options given below.**

11 Views|Posted a year ago

Asked by Alok Kumar Singh

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Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Phenolphtalein is a pH dependant indicator. It is a weak acid which is colourless in acidic medium but gives pink colour in basic medium. The pink colour is due to its conjugate form. Phenolphthalein dissociates in basic medium. Therefore, assertion is true but reason is false.

$\underset{(C o l o u r l e s s)}{H P h (a q .)} ? H^{+} + \underset{(P i n k)}{P h^{-}}$

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

For the equilibrium $A ⇌ B$ , the variation of the rate of the forward (a) and reverse (B) reaction with time is given by:

28 Views|Posted a year ago

Asked by Alok Kumar Singh

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Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

At equilibrium rate of forward and backward reaction becomes equal.

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

At 600K, 2 mol of NO are mixed with 1 mol of O₂.

2NO_(g) + O₂(g) $⇄$ 2NO₂(g)

The reaction occurring as above comes to equilibrium under a total pressure of 1 atm. Analysis of the system shows that 0.6 mol of oxygen are present at equilibrium. The equilibrium constant for the reaction is__________. (Nearest integer)

48 Views|Posted a year ago

Asked by Vishal Baghel

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Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$2 N O_{(g)} + O_{2 (g)} ? 2 N O_{2} (g)$

Initial moles2mol1 mol

At equilibrium (2 – 2x) mole (1 – x) mol2x mol

$n o_{2} \Rightarrow (1 - x) = 0.6$

$∴ x = 0.4$

$n_{N O} = 2 - 2 x = 2 - 2 \times 0.4$

= 2 0.8 = 1.2

$n_{N O_{2}} = 2 x = 2 \times 0.4 = 0.8$

$∴ K p = \frac{{(\frac{0.8}{2.6})}^{2}}{{(\frac{1.2}{2.6})}^{2} (\frac{0.6}{2.6})}$

= 1.925

the nearest integer = 2.

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

When 600 mL of 0.2 M HNO₃ is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ × 10^-² °C.

(Enthalpy of neutralization = 57 kJ mol^-¹ and Specific heat of water = 4.2 JK^-¹ g^-¹)

(Neglect heat capacity of flask)

8 Views|Posted a year ago

Asked by Vishal Baghel

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Answered by

Vishal Baghel | Contributor-Level 10

a year ago

HNO₃ + NaOH ® NaNO₃ + H₂O

t = 0, (600 × 0.2)_meq

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Which among the following is the strongest Bronsted base?

14 Views|Posted a year ago

Asked by Vishal Baghel

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Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Due the absence of inversion and non resonating nature

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

If the equilibrium constant for $A ⇌ B + C$ is $K_{(eq)}^{(1)}$ and that of $B + C ⇌ P$ is $K_{(eq)}^{(2)}$ , the equilibrium constant for $A ⇌ P$ is:

3 Views|Posted a year ago

Asked by Alok Kumar Singh

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Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

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New answer posted•a year ago

Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

pH value of 0.001 M NaOH solution is___________.

2 Views|Posted a year ago

Asked by Payal Gupta

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Answered by

Payal Gupta | Contributor-Level 10

a year ago

0.001 M NaOH solution has [OH^-] = 0.001 M = 10^-³ M

Using ; pOH = $- l o g_{10} [O H^{-}]$

= $- l o g_{10} 1 0^{- 3}$

pOH = 3

pH = 14 – pOH

pH = 14 – 3

pH = 11

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New answer posted•a year ago

Equilibrium Class 11th

What effect does a catalyst have on the equilibrium position of a reaction?
(a) A catalyst favours the formation of products
(b) A catalyst favours the formation of reactants
(c) A catalyst does not change the equilibrium position of a reaction
(d) A catalyst may favour reactants or product formation, depending upon the direction in which the reaction is written.

1 Views|Posted a year ago

Asked by Vishal Baghel

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Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Answer: (a) A catalyst favours the formation of products

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New question posted•a year ago

Equilibrium Class 11th

<p><strong> What effect does a catalyst have on the equilibrium position of a reaction?</strong><br>(a) A catalyst favours the formation of products<br>(b) A catalyst favours the formation of reactants<br>(c) A catalyst does not change the equilibrium position of a reaction<br>(d) A catalyst may favour reactants or product formation, depending upon the direction in which the reaction is written.</p>

4 Views|Posted a year ago

Asked by Vishal Baghel

New answer posted•a year ago

Equilibrium Class 11th

On addition of acetate ions to an acetic acid solution, the concentration of hydrogen ions, [H⁺]

(a) Becomes zero (b) Is unchanged (c) Increases (d) Decreases

3 Views|Posted a year ago

Asked by Vishal Baghel

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Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Answer: (d) decreases

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